No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5.
However, log10 5 = 1 - log102 = 2- log1020 .
or
log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4
But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
2 over 5 is an equivalent fraction for 20 over 50.
20/12 = 5/3
5 to 2
4/5.
divide 20 by 5 = 4 divide 25 also by 5 = 5 4/5
It could be that: 5 to 20 is equivalent 1 to 4
decimal equivalent to 5/20 = 0.25
1 pascal (Pa) is equivalent to 94 dBSPL. Reference sound pressure po = 20 µPa = 2×10^−5 Pa (Threshold of hearing) Reference sound pressure level Lpo = 0 dB-SPL (Threshold of hearing level) Get sound pressure level Lp in dB when entering sound pressure p = 1 Pa: Lp = 20×log (p / po) dB = 20×log (1 / 2×10^−5) = 20×log (1 / 0.00002) = 20×log (50000) = 94 dB.
5/20 = 0.25 <------------
No. 9/20 is 12.5% bigger than 2/5. 8/20 is equivalent to 2/5.
2logx-log5=-2 logx^2-log5=-2 log(x^2 / 5)=-2 x^2 / 5 = 10^-2 x^2=5(1/100) x^2=1/20 x=√(1/20)
5/20 = 1/4
5/20 = 1/4
5/20 = 1/4 in its simplest form
1/5 is equivalent to .20
20% = 0.2 or 1/5
20