Point (1,4) is NOT on the line x + 2y = 5
At what point does line represented by the equation 8x + 4y = -4 intersects the y-axis, and at what point in the negative direction of x-axis.
A line is represented by an equation. Each solution of the equation is a point on the line, and each point on the line is a solution to the equation. So the line is just the graph of the solution set of the equation.
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
There is no "equals" sign therefore "x-9" is NOT an equation.
The slope is -0.2
The slope is -4
The graph of [ y = 7 ] is a straight horizontal line, passing through the point [ y = 7 ]on the y-axis. The slope of a horizontal line is zero.
The y-intercept of a linear equation is the point where the graph of the line represented by that equation crosses the y-axis.
A linear equation is the equation of a line and that consists of an infnite number of points. What you have, in x = -4 and y = -1/3, is a single point. A single point is not a line and so there cannot be a linear equation (suitable for a line) to represent a point.
x = -3 represents a vertical line whose slope is undefined.
Without an equality sign the expression can not be considered to be an equation
5 and the y intercept is 2
It's the equation of a straight line. Every point on the line is a solution to the equation. There are an infinite number of them.
Yes its on the line.
The diagonal line collapses into a single point on that line.
Without an equality sign the given expression can't be considered to be a straight line equation.
It's the equation of a straight-line graph. Every point on the line is a solution of the equation. There are an infinite number of them.
it equals 1