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Q: Is 55 the sum of the first positive 10 integers?

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what is the sum of the first 10 positive integers? To me, if you include 0 as the first integer, then the tenth integer is 9 and the sum is 45. If you don't include 0, the tenth integer is 10, and the sum is 55.

The sum of the first ten positive integers, i.e. 1,2,3,4,5,6,7,8,9, and 10, is 55. The sum of the first ten negative integers, i.e. -1,-2,-3,-4,-5,-6,-7,-8,-9, and -10 is -55. The sum of the first ten positive integers plus the sum of the first ten negative integers is 0.

The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55

The flowchart to read 10 positive integers K>10 Start A N K=1 Sum = 0 Sum = Sum + K2 B Is Y Print K > 100? sum K=k+1 End B A

-4 and -6

Take any negative integers, say -5 and -10, their sum is -15 which is smaller than both of them. We could have used 0 as well, so I should have said any non-positive integers. To see that is does not work with positive integers, take 5 and 10 whose sum is 15 which is BIGGER than either one.

you can use the condition statement like for(i=0:i<=10;i++)

The sum of the digits is 6.

The first ten positive numbers total 55.

Many people would consider 0 to be the first even positive integer, however similar to the neutron in an atom, 0 holds a neutral position. Meaning it is neither a proton (+1) or electron (-1). So our first positive even integer would be 2.2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110, which is the sum of the first ten evenly positive integers.

The integers would begin with 10.

11

55

55

5 & 10

Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.

641

The integers are -14, -12 and -10.

The integers are 10, 11 and 12.

-10 and -14

They're all positive integers under 30.

There are 4 and they are 2 3 5 and 7

They are: 0, 2, 4, 6, 8 and 10

-10

The integers 2 and 10 have a product of 20 and a sum of 12.