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Q: Is the number of permutations of two items from a data set is always two times the number of combinations when taking two objects at a time from the same data set?
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Does the number of permutations always exceed the number of combinations?

No. The number of permutations or combinations of 0 objects out of n is always 1. The number of permutations or combinations of 1 object out of n is always n. Otherwise, yes.


How do you find permutation?

If there are n objects and you have to choose r objects then the number of permutations is (n!)/((n-r)!). For circular permutations if you have n objects then the number of circular permutations is (n-1)!


The number of permutations of n objects taken all together is?

The number of permutations of n objects taken all together is n!.


How many 4 number combinations are there using 1 2 3 4 5?

There are 120 permutations and 5 combinations.


How many5 number combinations are there in the numbers1to43?

On a calculator: 43C5 = 962598 This is for combinations and not permutations, so in essence, the order of the 5 number combinations does not matter. Yours Truly, Mr Greatness


Is the number of permutations of 2 items from the same data set always 2 times the number of combiations when taking 2 objects from a data set?

Yes


How many different combinations are possible is a coin is tossed once and a number cube is tossed twice?

The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.


How can you find the number of permutations of a set of objects?

If there are n different objects, the number of permutations is factorial n which is also written as n! and is equal to 1*2*3*...*(n-1)*n.


How many 3 number combinations are possible with 1234?

Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.


The number of permutations of 5 things taken 2 at a time is 20?

Not quite. Number of combinations is 20, number of permutations is 10. Any 2 from 5 is 10 but in any order doubles this.


What is the number of distinguishable permutations?

The formula for finding the number of distinguishable permutations is: N! -------------------- (n1!)(n2!)...(nk!) where N is the amount of objects, k of which are unique.


How many combinations are there if there are 8 numbers and you have a 16 number combination?

Assuming that "number" means digits and that it is permutations (rather than combinations) that are required, the answer is 816 which is 281.475 trillion (approx).