answersLogoWhite

0


Best Answer

If those are the only values, no.

User Avatar

Wiki User

8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Is the relation (1 3) (4 0) (3 1) (0 4) (2 3) a function?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Is this relation a function{(0, 0), (0, 1), (0, 2), (0, 4), (0, 5)}?

no


Is this relation a function{(0, 0), (1, 0), (2, 0), (3, 0), (4, 0)}?

yes


Which ordered pair could you remove from the relation 2 1 1 1 1 0 0 1 1 0 so that it becomes a function?

The first number in each pair must be unique.


How can you tell if a relation of a graph has a function?

A relation is any set of ordered pairs (x, y), such as {(2, 5), (4, 9), (-3, 7), (2, 0)} or {(2, 3), (5, -2)}. A function is a special type of relation in which each x-value is assigned a unique y-value. So in the two examples given above, the first relation is NOT a function because the x-value of 2 is assigned two different y-values: 5 and 0. The second example above is a relation, since each x-value given (i.e., 2 and 5) is only assigned to one y-value (i.e., 3 and -2, respectively). Two additional examples: {(0, 5), (1, 3), (1, 8), (4, -2)} is NOT a function, because the x-value of 1 is assigned to two different y-values. {(0, 3), (1, 4), (3, -2), (4, 7), (5, 0)} is a function, because there is no x-value that is assigned to more than one y-value. When graphed in the Cartesian plane, you can determine if a relation is a function or not by the "vertical line test", which says that if there is any place where a vertical line can be drawn that will pass through the graph more than once, then that relation is NOT a function. But if every vertical line that can possibly be drawn only passes through the relation at most once, then that relation is a function.


Which ordered pair could you remove from the relation (2 1) (1 1) (1 0) (0 1) (1 0) so that it becomes a function?

The right part of the relation needs to be unique - no numbers may be repeated. It's clear that in this case, you would need to remove more than one pair.


What are the kinds of relation in mathematics?

1. One to One -function- 2. One to Many -relation- 3. Many to Many -function-


Is this relation afunction (-32)(2-4)(26)(-3-5)(0 3)?

No, it is not a function.


Which ordered pair could you remove from the relation 1 0 1 3 2 2 2 3 3 1 so that it becomes a function?

Removing one pair is not enough to make it a function. You need to remove one of the pairs starting with 1 as well as a pair starting with 2.


Is (6 8) (-4 -1) (2 3) a function or a relation?

It is both.


How do you determine if you are given a set of ordered pairs that represent a function?

A relation is a set of ordered pairs.A function is a relation such that for each element there is one and only one second element.Example:{(1, 2), (4, 3), (6, 1), (5, 2)}This is a function because every ordered pair has a different first element.Example:{(1, 2), (5, 6), (7, 2), (1, 3)}This is a relation but not a function because when the first element is 1, the second element can be either 2 or 3.


What is the function for this function table x -3 -2 0 1 2 y 9 4 0 1 4?

Y = x2


Which of the ordered pairs below could NOT be in this function{(0, 0), (1, 1), (2, 2), (4, 3)}?

(2, 4)