True, because the slant height and the altitude, or height, of the pyramid form one leg and the hypotenuse of a triangle withing the pyramid, and the hypotenuse of a triangle is always the longest side- it is not possible for the hypotenuse to be equal to the legs of a right triangle. (It is a right triangle because an altitude is perpendicular to the base of a pyramid.)
It sounds like you're looking for the slant height.
slant height of the pyramid Louvre in Paris=28 meters
Its vertical height is that of the perpendicular from the centre of the base to the apex; the slant height is the length of the sloping "corner" between two faces. The height of a regular pyramid is the vertical distance from the center of base to the top and is usually shown with a line perpendicular to the base, denoted with a right angle to the base. The slant height it the height of the lateral face (the triangles) from the edge of the base to the top of the pyramid. It is the height of the triangle, not the pyramid itself. The slant height will also be the hypotenuse of a right angle formed from the altitude of the pyramid and the distance from the center of the base to the edge.
The slant height will be 25 cm
The height of the triangular face of a pyramid is called the slant height.
No, the slant height is the from the top vertex to the base of the base of the pyramid, it forms a 90 degree angle with the base and slant height. The lateral edge is literally the lateral (side) edge.
This pyramid would have a perpendicular height of 3, a volume of 64 units3 and a slant edge of 6.403
I would think that the slant is about 5m taller, although some pyramids have a different slant, so it depends.
The answer is given below.
1/2*perimetre of base*slant height
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm is: 64 cm3
By using trigonometry or Pythagoras' theorem
If you visualize the cone by cutting it vertically (with a plane perpendicular to the base), you can construct a right triangle to represent the radius, altitude, and slant height. This triangle has legs of 7 (the radius) and 19 (the altitude). Its hypotenuse represents the slant height. We can then use the Pythagorean theorem to solve for the slant height: 72 + 192 = s2 72 + 192 = s2 410 = s2 s = √(410) s ≈ 20.24 Therefore the cone has a slant height of √(410), or approximately 20.248456731316586933246902289901 units.
Surface area of a triangular pyramid: SA = 1/2 as + 3/2 sl a = altitude of the base triangle s = side of the triangle l = slant height of the pyramid.
On the off chance that the question refers to a right cone, l2 = r2 + h2 by Pythagoras, where l is the slant height, h the altitude and r the radius.
To find the slant height of an object (frustum or pyramid) you take the distance measured along a lateral face from the base to the apex along the centre of the face or in other words it is the altitude (height) of the triangle comprising a lateral face. (Kern and Bland 1948,p 50)
The slant height of a square pyramid is always perpendicular to the base. It is form the top vertex all the way down to the most center of one side of the base edge.
I don't know not mine