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Q: Log9x plus log x equals 4log10?

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Same as log(5x2) = log(10).

True

The explanation and answer to the following math equation to find x -0.3 plus 5-5 log (d) equals a plus 5-5 log 4 (d) is -5 log(d)+x+4.7 = a-5 log(4 d)+5. The solution is x = a-6.63147.

G(x) = log(2x) + 2, obviously!

It cannot be done because the base for the second log is not given.

log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107

How about 8*log(88/88) or 888*log(8/8)

2

You have, y = 6 + log x anti log of it, 10y = (106) x

log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1

Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.

log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4

The anti-log of what ??? If log(12) = 1.07918, then antilog(1.07918) = 12 Did you want the anti-log of 12 ? That's 1,000,000,000,000.

the value of log (log4(log4x)))=1 then x=

11

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No. Insert the word "minus" in place of the word "plus", and you'll have a true statement.

-Log(1.4x10-3)= 2.85 The Log to be used here is the decimal one, not the neperian one.

3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1

"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a

-log(1.5*10-11) = 9.8pH

- log(0.00097) = 3 pH ------------

log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3

logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999

It equals 0.4343