yes because √2 is irrational and √8= √[4*2]=2√2
The square root of 8 over 25 is irrational, and real.
The square root of 8 is irrational and real.
No it's 8, which is not irrational.
No, the square root of an irrational number is not always rational. In fact, the square root of an irrational number is typically also irrational. For example, the square root of 2, which is an irrational number, is itself irrational. However, there are exceptions, such as the square root of a perfect square of an irrational number, which can be rational.
irrational
irrational
It is an irrational number
The square root of 8 is an irrational number because it cannot be represented as a fraction of two integers.
The square root of 8 over 25 is irrational, and real.
The square root of 8 is irrational and real.
No it's 8, which is not irrational.
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc
The square root of 64 is 8 which is a rational number
The square root of 94 is an irrational number
The square root of 200 is irrational.
The square root of 2 is irrational, and therefore, this equation is unsolvable.