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yes exept for the numbers 3,9,15,21,27,33 etc

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Q: Is the sum of a number that is a multiple of 3 and a number that is a multiple of 6 must be a multiple of 6?

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Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)

A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.

Here are two solutions: 1234567890 and 9876543210. There are many more.To be a multiple of 6, the number must be both a multiple of 3 and a multiple of 2. If the sum of the digits is a multiple of 3, then the number is a multiple of 3. Adding up all digits (0 through 9) gives a sum of 45, which is a multiple of 3. Since addition is commutative, rearranging the digits in any order will still have a sum of 45, so it's still a multiple of 3. For it to be a multiple of 2, the last digit (the one's place) must be {0,2,4,6, or 8}

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

If the sum of the digits is a multiple of three, the whole number is a multiple of three.

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Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)

A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.

you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!

Here are two solutions: 1234567890 and 9876543210. There are many more.To be a multiple of 6, the number must be both a multiple of 3 and a multiple of 2. If the sum of the digits is a multiple of 3, then the number is a multiple of 3. Adding up all digits (0 through 9) gives a sum of 45, which is a multiple of 3. Since addition is commutative, rearranging the digits in any order will still have a sum of 45, so it's still a multiple of 3. For it to be a multiple of 2, the last digit (the one's place) must be {0,2,4,6, or 8}

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

If the sum of the digits is a multiple of three, the whole number is a multiple of three.

2452 divided by 4 = 6132452 divided by 3 = 817.3333 recurring

3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57

24

No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.

15

No. To check if a number is a multiple of 3 add its digits together and if this sum is a multiple of 3, then so is the original number. This sum can be continued until a single digit remains; if the single digit is 3, 6 or 9 then the original number is a multiple of 3, otherwise not. 19 → 1 + 9 = 10 10 → 1 + 0 = 1 which is not 3, 6 or 9, so 19 is not a multiple of 3.