There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.There aren't any. 340 is divisible by 4 while the sum of any two consecutive even numbers cannot be divisible by 4.
There is no possible answer. The sum of two consecutive even numbers MUST leave a remainder of 2 when divided by 4. That is, the sum must be divisible by 2 but must not be divisible by 4.
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
Three consecutive whole numbers can be written as x, x + 1 and x + 2. Added together, their sum can be written as 3x + 3. Not only is that sum divisible by three, but by doing so [3(x + 1)] you can see that the sum is also equal to three times the second number.
Yes, that is true.
The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.
5+2+1=8 and 8 is not divisible by 3.
Since one of the numbers will be even and the other odd, the sum will always be odd.
Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.
yes,sum of 2 even numbers is always divisible by 2.
All odd numbers are the sum of two consecutive numbers. Odd multiples of 7 less than 25 are 7 and 21.
The sum is always 3 more than (triple the smallest number).
yes always this is true' example 1,2,3 sum is 6 and is divisible by 3
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
There is no solution. The sum MUST be an even number that is NOT divisible by 4. Negative 88 is divisible by 4
Yes, if the first number is odd.
If you mean six consecutive INTEGERS, then the answer is Yes.
There is no solution. You could do it if the numbers were odd: 25 and 27 are consecutive odd numbers that equal 52.
The sum of consecutive integers will always be odd. Consecutive odd numbers will be even. 299 + 301 = 600
The sum of any two consecutive whole numbers is always odd, and equal to one more than twice the first number (2x+1).
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
No two consecutive integers have a sum of 2012.
The sum of the first 350 consecutive odd numbers is 122,500.