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Twos complement of a given 3 or more bit binary number of non-zero magnitude is the same the original number if all bits except the?
ANSWER: MSB IS 1 In the 2's complement representation, the 2's complement of a binary number is obtained by first finding the one's complement (flipping all the bits), and then adding 1 to the result. This representation is commonly used to represent signed integers in binary form. Now, if all bits except the sign bit are the same, taking the 2's complement of the binary number will result in the negative of the original number. The sign bit (the leftmost bit) is flipped, changing the sign of the entire number. For example, let's take the 4-bit binary number 1101 The 2's complement would be obtained as follows: Find the one's complement: 0010 Add 1 to the one's complement: 0011
I am a number between 24 and 34 you get to me when you count by twos you get to me when you count by fives what number am I?
30
How do you represent -123 in twos complement in 10 bits register?
-123 = 11 1000 0101 [I presume the number 123 is in decimal] First write the positive number in binary using 10 bits (I've split it into groups of 4 bits to make it easier to read): 123 = 00 0111 1011 Convert to 1s complement by inverting all bits (any 0 => 1, any 1 => 0): 00 0111 1011 => 11 1000 0100 Finally add 1 to get 2s complement: 11 1000 0100 + 1 = 11 1000 0101 Thus the 2s complement of the negative number: -123 = 11 1000 0101 This can also be expressed in hexadecimal: -123 = 0x385 Or in octal (easy to convert if the binary number is first written in groups of 3 bits): -123 = 1 110 000 101 = 01605 [I've used C notation for the hexadecimal and octal numbers.]
Subtract the hexadecimal number 1234 from DA57 using twos complement addition method?
(1234)hex=(0001 0010 0011 0100)2 (DA57)hex=(1101 1010 0101 0111)2 Taking, (1234)hex=(0001 0010 0011 0100)2 =(1110 1101 1100 1011) -1s complement =(1110 1101 1100 1100) -2s complement Now ,add 2s complement of (1234)hex with (DA57)hex, we get 1110 1101 1100 1100 + 1101 1010 0101 0111 1 1100 1000 0010 0011 There is a Carry bit Since,carry is generated.so,no is negative Then take 2s complement of above no.Thus ,we get 0011 0111 1101 1101=(37DD)hex (1234)hex -(DA57)hex =37DD)hex
Is 12 an odd number or even number?
12 is an even number, if you just count up by twos . observe, 2,4,6,8,10,12,14,16,18,20.... and so on .
What is the number 0111111111111111 in twos complement?
100000000000001
The twos complement of 11001101 is?
00110011 is the 2's complement for this unsigned number and 10110011 if this is a signed number
How do you write a program to determine whether a number is odd or even counter?
For positive integers, if the least significant bit is set then the number is odd, otherwise it is even. For negative integers in twos-complement notation, if the least significant bit is set then the number is odd, otherwise it is even. Twos-complement is the normal notation, allowing a range of -128 to +127 in an 8-bit byte. For negative integers in ones-complement notation, if the least significant bit is set then the number is even, otherwise it is odd. Ones-complement is less common, allowing a range of -127 to +127 in an 8-bit byte, where 11111111 is the otherwise non-existent value -0 (zero is neither positive nor negative). Ones-complement allows you to change the sign of a value simply by inverting all the bits. Twos-complement is the same as ones-complement but we also add one. Thus the twos complement of 0 is 0 because 11111111 + 1 is 0 (the overflowing bit is ignored). 11111111 then becomes -1 rather than the non-existent -0.
Why do you get an even number when you add two even numbers?
An even number is always some quantity of 'twos' (2's), and any quantity of twos is an even number. The first even number is a quantity of twos, and the second even number is another quantity of twos. When you add the first quantity of twos to the second quantity of twos, you get a new quantity of twos. Since the new quantity of twos is a quantity of twos, it's an even number.
10 Why is twos complement usually used to represent integers?
The advantage of the two's complement method is that the procedure for adding or subtracting numbers is the same, whether the numbers are positive or negative. This makes the hardware for managing these numbers simpler.
Twos complement of a given 3 or more bit binary number of non-zero magnitude is the same the original number if all bits except the?
ANSWER: MSB IS 1 In the 2's complement representation, the 2's complement of a binary number is obtained by first finding the one's complement (flipping all the bits), and then adding 1 to the result. This representation is commonly used to represent signed integers in binary form. Now, if all bits except the sign bit are the same, taking the 2's complement of the binary number will result in the negative of the original number. The sign bit (the leftmost bit) is flipped, changing the sign of the entire number. For example, let's take the 4-bit binary number 1101 The 2's complement would be obtained as follows: Find the one's complement: 0010 Add 1 to the one's complement: 0011
How do you write a basic program find whether number is even or odd if even display its square and if odd display its cube?
Divide that number into 2 using modulus division. Modulus division get the remainder of the division. If it has no remainders, then it's an even number. If not, then it's an odd number. Here's a pseudo code of the program. ALGORITHM ODD_EVEN INPUT (number) IF (number MOD 2 == 0) THEN DISPLAY ("Even") ELSE DISPLAY ("Odd") END IF END ODD_EVEN Amendment: You did ask for a BASIC program: 10 INPUT X: IF X = 999 THEN STOP 20 PRINT X;: IF X/2 = INT(X/2) THEN PRINT "EVEN" ELSE PRINT "ODD" 30 GOTO 10
How do you programme Twos complement in binary in c?
int complement (int n) { return -n; } or int complement (int n) { return ~n+1; } both does the same thing.
What is unsigned data types in turbo c?
The same as an unsigned type in any other implementation of C. An unsigned type is an integer that is guaranteed positive. Normally, the most-significant bit of an integer denotes the sign (positive or negative). Unsigned types use this bit to denote value, effectively doubling the range of positive values over that of the signed equivalent. For instance, a signed char has a guaranteed range of -127 to +127 while an unsigned char has a guaranteed range of 0 to 255. Note that a signed char typically has a valid range of -128 to +127, however this is only true on systems that utilise twos-complement notation. Those that use the older ones-complement notation have two representations for the value zero (one positive, one negative). Ones-complement simply inverts all the bits of a value to switch the sign of a value, whereas twos-complement adds the value 1 after inverting all the bits. The value zero is denoted as 00000000 in binary. Inverting the bits creates 11111111, which is minus zero on a ones-complement system and -1 on a twos-complement system. -1 + 1 is 0, hence we add 1 on a twos-complement system.
What are factors of 1934 that add up to 80?
1854
What is is the mixed number for three twos?
The answer to three twos is an integer and not a mixed number.
What is the difference between the twos complement representation of a number and the twos complement of a number?
Let's consider any number, for example a byte of data represented as eight bits. The values that this byte can have are 00000000 through 11111111. The easiest way to find the one's complement is to change the zeros to one and the ones to zeros. The limits shown above can be represented as 00 through FF in hexadecimal. Let's consider a number AF which is within this boundary. The easiest way to find the one's complement when numbers are represented in hexadecimal form is to subtract the number from (in this case) FF. You will have more F's depending on the length of the number you want to find the one's complement for. If the number consists of three hex digits then you subtract from FFF, if four then from FFFF and so on. Thus with our example of AF, its one's complement would be FF AF --- 50 --- If you add 1 to this result you will get the two's complement of the number AF. Hence the two's complement of AF is (50 + 1) = 51 in hex. Observe that the process of finding one's complement or two's complement of a number are reversible and the original number is obtained. Thus the one's complement of the one's complement of a number gives the original number. The two's complement of the two's complement of a number gives the original number. Lets consider the hex number FF. Its one's complement is 00 and the two's complement is 01. So far we have talked about two's complement of a number (and in the process the one's complement as well). It is not possible to explain two's complement representation without understanding hardware implementation on a computing device, namely, a computer. Let's consider a byte machine where you can operate only on single bytes. Thus you can add two bytes, subtract a byte from another and so on. If two's complement representation of numbers is not implemented on a machine, then the byte can hold values hex 00 through hex FF which would be 0 through 255 in decimal. If 1 is added to a byte containing FF on this machine, the contents of the byte will change to 0 and the overflow bit in the computer will be set to TRUE. If however, two's complement representation of numbers is implemented on a machine the MSB (most significant bit) in the byte is the sign bit. If it is set then the number is negative and if it is not set then the number is positive. Since one bit of the 8 bits in our byte machine is taken up to represent the sign, only the remaining 7 bits can hold the magnitude of the number. The range of positive number in such a machine is hex 00 through hex 7F which is 0 through 127. If you add 1 to 7F then the contents of the byte would be hex 80. Notice that this is a negative number because the MSB is set. But how negative is this number. Since the machine implements two's complement representation of number on this machine, subtract (hex 80) from hex FF and add 1 to get hex 80 which equals 128. So the byte machine which implements two's complement can represent values from -128 through +127. In general if a machine implements 16, 32, or 64 bit architecture, the numbers that they can hold if they implement two's complement are between -(2*n) through and including +(2*n - 1) where n is 16, 32, or 64. I hope you have a better understanding of the difference between two's complement of a number and its representation (meaning implementation) on a computer.
