No. If any number is divisible by 5 and 6, it must also be divisible by 30, which means that it must end with a zero.
Just write any digit or digits you want, then follow that by eight zeros.
A Thousand digit number will have 999 zeros
1234
A one to three digit number followed by six zeros is millions
100000000.
A number with 18 zeros is a quintillion so a 20 digit number would be 10's of quintillion's.
999900
The number with the smallest absolute value is 111111.
No. (Assuming a three digit number is in the range 100-999 and excludes leading zeros, that is 080 does not count as it is really 80 which is a two digit number) To be divisible by 11, the difference in the sums of the alternate digits of the number must be divisible by 11 (or 0). For a three digit number, this means that the sum of the first and last digits less the second digit must be a multiple of 11 (or 0). For a three digit number with all the digits the same, this calculation results in the value of one of the digits (eg 333 → 3 + 3 - 3 = 3) which will not be 0, and cannot be a multiple of 11 as a single digit is less than or equal to 9 which is less than 11 and thus not a multiple of 11.
300Hope this helps xx
12,345 there are many other possibilities though (ex: 83,921)
Assuming you mean whole numbers and leading zeros do not count, the smallest 3 digit number is 100.