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Q: Is 1155 divisible by four different prime numbers?

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Yes. 1155 = 3 * 5 * 7 * 11

1155, 3x5x7x11=1155.

The factors of 1,155 are: 1, 3, 5, 7, 11, 15, 33, 35, 77, 105, 165, 231, 385, and 1,155. 3, 5, 7, and 11 are prime numbers.

prime numbers that divide into 1155 = 3, 5, 7, 11

1155 is a composite number because it ends with 5. All numbers that end with 5 except 5 itself are composite numbers because they are divisible by 5, which means there are at least three factors, 1, 5, and the number itself.

1155 ends with 5, which means it is divisible by 5. It is a composite number because it has factors in addition to 1 and itself.

3 x 5 x 7 x 11 = 1155

1153 and 2

The factors of 1155 = 1, 3, 5, 7, 11, 15, 21, 33, 35, 55, 77, 105, 165, 231, 385, and 1155. The prime factors of 1155 are 3, 5, 7, 11.

3, 5, 11

Any number ending in 5 (or 0) is divisible by 5 and is therefore composite. The only exception is 5 itself which is prime.

1155 is not prime. 1155 = 3 * 5 * 7 * 11

1155 is composite.

No.

1155

1155

As a product of its prime factors: 3*5*7*11 = 1155

A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite. 1155 is composite.

3 5 7 and 11 they are all prime numbers

As a product of its prime factors: 3*5*7*11 = 1155

They can be 3*5*7*11 = 1155

1155 = 3 x 5 x 7 x 11

3 x 5 x 7 x 11 = 1155

3 x 5 x 7 x 11 = 1155

1155 = 3 x 5 x 7 x 11