No. For purposes of combining "like terms", you need terms that have exactly the same variables, with the same exponents (if there are any).
No, they are not.
If you are trying, for example, to find y in terms of x, you want to get an equation with only y on one side equal to an equation with x in it on the other side.
(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.
Please dont mind the βwhatβ
53,11 x+y=64 x-y=42 combine terms 2x=106 x=53 substitute x and solve for y 53+y=64 y=11
Follow this example. f(x) = (x+3)/5 To find its inverse, write y=f(x) y= (x+3)/5 Interchange x and y x = (y+3)/5 solve for y in terms of x 5x=y+3 y=5x-3 The inverse of f(x) is f^-1(x) = 5x-3
x+y+x =2x +y... I got this by simply combining like terms. I added the x's( 2x) and kept the y there which gave the answer
X (or Y) = (one value)
one that won't talk to one another because they don't like each other... NO, seriously, they are terms that are different. For example x^2+2x+3x-4x^2. The x^2 terms are like terms and the x^2 terms and the x terms and unlike because they are different. Just like x and y, or apples and oranges.
y = x + 2 y = 2 - x so x + 2 = 2 - x Combining like terms: 2x = 0 so that x = 0 and then, from the first equation, y = 2
No. It represents a function of x in terms of y but, in strict mathematical terms, not a function of y in terms of x. This is because the mapping from the domain (x values) to the range (y values) is 1-to-many. For each value of x, there can be 2 values of y. For example, x = 0 gives y2 = 1 so that y = ±1.
Yes, because they both contain the variable "x". y and 9x would not be like terms because they don't have the same variable. x and 9x2 would not be like terms because the variables are not raised to the same power.
In mathematical terms, a number x is less than y if y - x is positive.
9
Put x = 0 in the equation for y in terms of x.
x + 5y = 0 so x = -5y or y = -x/5 You can express x in terms of y or y in terms of x but it is not possible to solve a single linear equation in two variables.
i think it would be like this: 4:25 :: 1:6.25
x= z2 - 3