20 dimes and 30 nickles.
20 pennies = 20 08 nickels.. = 40 02 dimes... = 20 --- ................ --- 30 ................ 80
there r 40 nikels
The combinations depend on how many are dimes and how many nickels.
in US dollars: one dollar coin two dimes three nickels and three pennies
You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.
13 nickels 7 dimes
ms lynch has 21 coins in nickels and dimes. their total value is 1.65. how many of each coin does she have
7 quarters 2 dimes 4 nickels
40 Dimes and 8 Nickles
He has jillian.
7 nickels, 4 dimes, 3 quarters
You would have 7 nickels and 13 dimes. (7 x $0.10) + (13 x $0.05) = $1.35
7 nickels, 4 dimes, and 3 quarters.
20 pennies = 20 08 nickels.. = 40 02 dimes... = 20 --- ................ --- 30 ................ 80
20 dimes = 2.00 20 nickels = 1.00 Total = 3.00
If one-fifth of the coins are dimes two fifteeths are nickles and two-thirds are pennies how much of each coin do you have for a total of one dollars worth of coins.
there r 40 nikels