The first step in solving this problem is to build two equations. 0.25Q+0.10D=2.50 and Q+D=13 where Q=total number of quarters and D=total number of Dimes. Next we try to subtract one equation from the other to eliminate one variable. So we multiply 0.25Q+0.10D=2.50 by 4 to get 1Q+0.4D=10. Then we subtract Q+0.4D=10 from Q+D=13. This results in 0.6D=3. We divide both sides by 0.6 and end up with d=5. Therefore we have 5 dimes, which equals 50 cents. Therefore we have $2 in quarters or 8 quarters. 8 quarters is the answer.
8 of them.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
You have in your pocket a nickel and a quarter. (One of them is not a quarter- The other one is.) :)
50
(1/5)*(1/4) = 1/20 the odds of a quarter falling out, multiplied by the odds of a quarter falling out after a single quarter has fallen out
8 quarters, 5 dimes
8 of them.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
You have in your pocket a nickel and a quarter. (One of them is not a quarter- The other one is.) :)
10 quarters and 50 pennies
At least 1 of the coins must be a quarter (the 5 cent part), so there are exactly 3 ways to make $1.25 with either dimes and quarters or just quarters:1 quarter, 10 dimes3 quarters, 4 dimes5 quartersIf you have to use both coins, there are only the 2 ways shown.
A quarter plus a quarter is a half. In U.S. coins, two quarters equals 50 cents.
40 Quaters are in a roll of quarters
1 US quarter has a thickness of 1.75 millimeters. A 1-inch stack of quarters would be about 15 quarters.
1 quarter = 25 cents therefore 17 quarters = 4.25 dollars
50
You could have 5 quarters or 10 dimes and one quarter or several other combinations of coins.