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Length of rectangle is 3 times as great as its width. if the perimeter of the rectangle is no more than 72 cm. What is the length of the rectangle?
Wiki User
∙ 14y ago
The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
Wiki User
∙ 14y ago
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A certain rectangle has a width that is half the difference of the length and 6 cm If the Perimeter of the rectangle is 87 cm what is the length and width of the rectangle?
Algebra works great here. Let's use three variables: P for perimeter, L for length and W for width. Then we can rewrite the above in terms of math:W = (1/2)(L - 6)
A rectangle had an area of 24ft2 what is the length and width of the rectangle with the greatest perimeter?
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
How do you find the length of the longer side of the trapezium if the difference between the lengths of the two parallel sides is 2 cm?
With great difficulty. Or to put it another way, you also need to know the distance between the two parallel sides and the offset of the two parallel sides.
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PRINT "Give me the rectangle's length.": Input L PRINT "Give me the rectangle's width.": Input W PRINT "The rectangle's area is "; L x W PRINT "The rectangle's perimeter is "; 2 x (L + W) PRINT "You've been a great audience. I'm here til Thursday. Don't forget to tip your waiter. Have a nice day."
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With great difficultly. The area could be any value greater than 0 units2 and less than or equal to the area of a square with the given perimeter which would be 1/16 x perimeter2 units2. To know which of the possible areas you would need to know the length of one side, then you can work out the area: perimeter = 2 x (length + width) ⇒ width = (1/2 x perimeter) - length ⇒ area = length x width = length x ((1/2 x perimeter) - length) = (1/2 x perimeter x length) - length2
What is the length and width of a perimeter of 100ft?
Assuming that the length is at least as great as the width, the length can have any value, L, between 25 and 50 feet. The width, W, then would be 50 - L feet.
A certain rectangle has a width that is half the difference of the length and 6 cm If the Perimeter of the rectangle is 87 cm what is the length and width of the rectangle?
Algebra works great here. Let's use three variables: P for perimeter, L for length and W for width. Then we can rewrite the above in terms of math:W = (1/2)(L - 6)
A rectangle had an area of 24ft2 what is the length and width of the rectangle with the greatest perimeter?
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
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