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Since both the numerator and the denominator approach zero, the conditions for de l'Hospital's rule are fulfilled. Take the derivate of both the numerator and the denominator, and take the limit of the new fraction:

lim (t2-2)/(t-4) = lim 2t / 1 = 8 / 1 = 8.

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13y ago
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Q: Limit as t approches 4 square t minus 2 divided by t-4?
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