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Here are the binary numbers from zero to fifteen: 0 = 0000 1 = 0001 2 = 0010 3 = 0011 4 = 0100 5 = 0101 6 = 0110 7 = 0111 8 = 1000 9 = 1001 10 = 1010 11 = 1011 12 = 1100 13 = 1101 14 = 1110 15 = 1111
False
Yes. It must be at least one of the numbers on the list. If there is the same amount of each number, then there is no mode.
This is simple question to said that there are the whole numbers are started with 0 like that 0,1,2,3,4,5,6,........ and so on.
Whole numbers are numbers 0, 1, 2, 3, ..., up to infinity. And -1, -2, -3, ... down to "negative" infinity
The integers are the set { ...,-3,-2,-1,0,1,2,3,...} where the ... means that the list continues forever. Since this set includes the negative numbers whihc are not whole numbers, the answer would be no. The whole numbers are the set {0,1,2,3,...}
The list of whole numbers that are divisible by XXX is infinite. The first four are: 100, 200, 300, 400 . . .
There are an infinite list of different numbers, but only 90 of them are integers (whole numbers).
Exactly the same way you do when they're all whole numbers, or there are more than three numbers, or they're a mixture of whole numbers and decimals: -- Add up all the numbers on the list. -- Divide the big sum by the number of items on the list.
"41 and 50" is a list of two whole numbers. There's no procedure defined for making a decimal out of two whole numbers.
The integers are the set { ...,-3,-2,-1,0,1,2,3,...} where the ... means that the list continues forever. Since this set includes the negative numbers whihc are not whole numbers, the answer would be no. The whole numbers are the set {0,1,2,3,...}
The integers are the set { ...,-3,-2,-1,0,1,2,3,...} where the ... means that the list continues forever. Since this set includes the negative numbers whihc are not whole numbers, the answer would be no. The whole numbers are the set {0,1,2,3,...}