8
Assuming the shirts and pants are all different and that an "outfit" consists of one shirt and one pair of pants and that Jimmy is using these shirts and pants to make his outfits, there are 42 possible combinations.
59
3 x 5 x 3 = 45 If you can wear one each of two different pairs of shoes, then there are four possible items that can be changed: pants, shirts, left shoe, right shoe. The corresponding available options number 3 x 5 x 3 x 3 = 135 outfits.
10 you should be able to do this it's just 5*2
Assuming that you wear one of each every time (including a tie!), and that there are 3 pairs of boots, there are 4*3*2*3 = 72 combinations.
How many different outfits are possible from six shirts, four pairs of pants, and five pairs of socks?
12 outfits
Assuming the shirts and pants are all different and that an "outfit" consists of one shirt and one pair of pants and that Jimmy is using these shirts and pants to make his outfits, there are 42 possible combinations.
24
15 outfits. Simple Math
45 outfits
A lot
There are 30 outfit possibilities. Normally for a problem like this you just have to multiply all the numbers, but the trick to this question is to first add the number of shirts. If you don't, then some of your outfits will be a sweater and dress shirt with no pants, which isn't an outfit. So you have a total of 10 shirts and 3 pairs of pants, and when you multiply them you get a total of 30 outfits.
All you have to do is multiply them together: 5 shirts x 6 pants x 2 shoes = 60 different outfits.
Assuming an outfit is one shirt, one pair of pants and one pair of shoes, there are 24 different outfits.
5*8*3 = 120 outfits.
160 outfits