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Q: Make a two-digit number in which both digits are the same and the sum of the digits is eight?

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Eight digits.

By rearranging the digits, it is 9861.

A number is divisible by 8 if and only if it is an integer and the last three digits make a number that is divisible by 8. A general divisibility rule for 2^n where n is an integer is to take the last n digits and if they make a number that is divisible by n then it is divisible by n.

The highest number you can make out of the digits 2 4 0 and 1 is 4210.

9861

You can always tell a number is divisible by eight by checking to see if the rightmost three digits are. If they are, then the whole number is. With that in mind then, you can make up all sorts of such numbers by just grabbing some combination that you know is divisible by eight, and tacking additional digits on to the left. For example, we know that 128 is divisible by eight (128 / 8 = 16), so any of these numbers are as well: 89469128 13948128 90173128 The number of digits doesn't matter, so we also know that a ridiculously large number like this one: 25098174509840582437575109283102477568758134024 is divisible by eight, because the last three digits are.

9876 is the largest four digit number you can make if all the digits must be different.

Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.

8643

infinite

531

9827

There are 5 digits figures or alphabet that make a Benz C200 V6 engine. number?

get the numbers and order them from biggest to smallest.

Add

It could be: 4760 = 1

8642

98765.

974

It is 4579.

descending order

1047but, with a decimal, you can make an even smaller number:.0147

9

To count the number of times a digit occurs in an integer, start by initializing an array of ten counts of digits, such as int digits[10];Then, in a loop while the number is non zero, increment the element in the digits array that corresponds to the units digit, and then divide the number by ten, such as digits[number%10]++ and number/=10;int digits[10];int i;int number = some number;for (i=0; i

0.0001 because if you add zeroes to the decimal to make them have the same number of digits you will add zeros to 0.0001 to make it have the same number of digits and you get 0.000100 and it is greater than 0.000008