Best Answer

Width = 6 feet

Length = 24 feet

Q: Martin fenced a rectangular pen for his dog he used 60 feet of fencing the length of the dog pen is 4 times its width what are the width and length of the pen?

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2*length+2*width = perimeter Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 Divide both sides by 10 to find the value of x: x = 6 Therefore: length = 24 feet and the width = 6 feet

length and width

If the sides of a rectangle (not rectangular) are X and Y units, then the corner to corner length - the diagonal - is sqrt(X2 + Y2)

A cube is a rectangular prism in which each edge is of the same length.

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Number of fencing panels required = Roundup(Length of fencing required/Panel length) There is no information in the question about the area to be fenced, so there is no simple formula to calculate the length of fencing required. It is assumed that the fencing panels used are all of the same length.

2*length+2*width = perimeter Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 Divide both sides by 10 to find the value of x: x = 6 Therefore: length = 24 feet and the width = 6 feet

832 yards

4Improved Answer:-30 feet of fencing will be needed

The length of the field is 250 meters. As we know the field is a rectangle, you can divide the amount of fencing in 2, which would be 400 meters. This will provide you with enough fencing for one end and one side. To determine the actual length of the side you would take your 400 meters and subtract the end length which is 150 meters, leaving you with a side length of 250 meters.

the park is 30m x 90m

Divide the length of the fencing by pi.

I didn't know that chickens fenced! But, to be serious, it depends upon the type of mesh, its height and how much length you require. I always look in Wilkinsons but you may not have heard of them, The place to ask is a hardware specialist or a Do It Yourself shop.

Yes, so what is the problem?

Length of fencing needed = 2*pi*10 = 20*pi feet

Assuming a rectangular plot, the perimeter is 2(Length + Width) = 2*(256 + 178) = 2*434 = 868 ft.

length and width