Width = 6 feet
Length = 24 feet
2*length+2*width = perimeter Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 Divide both sides by 10 to find the value of x: x = 6 Therefore: length = 24 feet and the width = 6 feet
length and width
If the sides of a rectangle (not rectangular) are X and Y units, then the corner to corner length - the diagonal - is sqrt(X2 + Y2)
The longer of the sides forming the rectangular base of the pyramid.
A cube is a rectangular prism in which each edge is of the same length.
Number of fencing panels required = Roundup(Length of fencing required/Panel length) There is no information in the question about the area to be fenced, so there is no simple formula to calculate the length of fencing required. It is assumed that the fencing panels used are all of the same length.
2*length+2*width = perimeter Let the length be 4x and the width be x: 2(4x+x) = 60 8x+2x = 60 10x = 60 Divide both sides by 10 to find the value of x: x = 6 Therefore: length = 24 feet and the width = 6 feet
832 yards
4Improved Answer:-30 feet of fencing will be needed
The length of the field is 250 meters. As we know the field is a rectangle, you can divide the amount of fencing in 2, which would be 400 meters. This will provide you with enough fencing for one end and one side. To determine the actual length of the side you would take your 400 meters and subtract the end length which is 150 meters, leaving you with a side length of 250 meters.
the park is 30m x 90m
Divide the length of the fencing by pi.
I didn't know that chickens fenced! But, to be serious, it depends upon the type of mesh, its height and how much length you require. I always look in Wilkinsons but you may not have heard of them, The place to ask is a hardware specialist or a Do It Yourself shop.
Yes, so what is the problem?
Length of fencing needed = 2*pi*10 = 20*pi feet
Assuming a rectangular plot, the perimeter is 2(Length + Width) = 2*(256 + 178) = 2*434 = 868 ft.
length and width