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Mass is 145g and velocity is 25ms Find the answer using kinetic energy formula?
Wiki User
∙ 9y ago
Kinetic energy is 0.45 joules using the formula Ek = ½ x mv2
Wiki User
∙ 9y ago
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What do you call the energy of moving objects?
Kinetic Energy; usually calculated using the formula: Ek = 0.5 mv2 Where Ek is the kinetic energy, m is the mass and v is the velocity (speed).
What is kinetic energy measured with?
Kinetic energy is calculated using mass and velocity. KE=1/2mv2
What formula do you use to caculate kinetic energy?
Ek = 0.5mv2Kinetic energy equals half times mass times the square of the velocity. Using SI units, mass in kilograms and velocity in metres per second, the energy will be in Joules.
You can calculate kinetic energy by using the equation what?
KE=1/2*m*v2whereKE is kinetic energym is the massand V is the velocity
What is the kinetic energy of a 72 kg sky diver falling at a terminal velocity of 79 m per s show your work?
His kinetic energy is 5,688 kilogram-meters.Now you do the calculation, and if you arrive at the same solution,then you'll know that your work is correct.
What do you call the energy of moving objects?
Kinetic Energy; usually calculated using the formula: Ek = 0.5 mv2 Where Ek is the kinetic energy, m is the mass and v is the velocity (speed).
What is kinetic energy measured with?
Kinetic energy is calculated using mass and velocity. KE=1/2mv2
How do you calculate velocity using kinetic energy?
KE= 0.5mv2 so we have KE=50 m=50 v=1.414m/s
What formula do you use to caculate kinetic energy?
Ek = 0.5mv2Kinetic energy equals half times mass times the square of the velocity. Using SI units, mass in kilograms and velocity in metres per second, the energy will be in Joules.
You can calculate kinetic energy by using the equation what?
KE=1/2*m*v2whereKE is kinetic energym is the massand V is the velocity
What is the energey of motion?
kinetic energy. found using 1/2*mass*(velocity^2)
What is the kinetic energy of a 72 kg sky diver falling at a terminal velocity of 79 m per s show your work?
His kinetic energy is 5,688 kilogram-meters.Now you do the calculation, and if you arrive at the same solution,then you'll know that your work is correct.
A 2 kg object is dropped from a height of 12 m Using the conservation of energy calculate the speed it has at the end of the 12 m fall?
Use the formula KE = (1/2)mv2 (kinetic energy equals 1/2 times mass times the square of the velocity).Use the formula KE = (1/2)mv2 (kinetic energy equals 1/2 times mass times the square of the velocity).Use the formula KE = (1/2)mv2 (kinetic energy equals 1/2 times mass times the square of the velocity).Use the formula KE = (1/2)mv2 (kinetic energy equals 1/2 times mass times the square of the velocity).
How do you find change in velocity?
when using energy use the kinetic energy equation for change KE = .5(M)(Vf^2 - Vo^2) M = mass Vf = fianal velocity Vo = initial velocity
How do you show mathematically why a small increase in your vehicle's speed results in a tremendous increase in your vehicles kinetic energy?
The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.
What is the equation used to compute the velocity of a falling object using energy?
Calculate the initial potential energy (PE = mgh). Assume that all of this gets converted to kinetic energy, and solve for velocity (KE = 0.5 mv2).
If a 2kg metal ball hits a 1kg wooden ball at a speed of 3ms and the metal ball continues at a speed of 1ms how fast is the wooden ball going?
This question is all about kinetic energy. Kinetic Energy = 0.5 * mass * velocity^2 Firstly we must assume that no energy is lost to heat and sound, so that kinetic energy is constant throughout the contact. The initial kinetic energy is all in the 2kg metal ball. Using the above formula we find that the energy is 0.5 * 2 * 3^2 = 0.5 * 2 * 9 = 9 J The final kinetic energy must be the same (because of our assumption). The metal ball has a kinetic energy of 0.5 * 2 * 1^2 = 1 J, so the wooden ball must have the remainder, which is 8 J. 8 = 0.5 * 1 * velocity^2 velocity^2 = 16 velocity = square root of 16 velocity = 4 m/s
