Q: Mimi had 174 to buy tickets to a concert The adult tickets cost 10.50 and the student tickets cost 7.50 She bought 4 more student tickets than adult tickets How many student tickets did she buy?

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8 Adult tickets

870 + 540 = 1410

Your question lacks the info necessary to answer it.How many tickets were sold in total?What percentage of either student or adult tickets sales were sold?Your question cannot be answered as written.

Adults: 325 Student: 175

answer is 325 adult tickets were sold ( fmtickets.com )

220 Tickets at 3 = 660 241 Tickets at 4 = 964 ---------------------------- 461 1624

325 Tickets sold to adults 400 tickets sold to students

If A is number of adult tickets, and B is number of student tickets, we get a system of two equations for two unknowns: 4A+2B=2446 A+B=920 By solving this system, we obtain B=617

67 adult ticket 58 student tickets total cost $413 total tickets 125 just set up a set of simultaneous equations such as if number of adult tickets is x and number of student tickets is y x+y=125 since 125 tickets are being bought then multiply amount of tickets by ticket cost 4x+2.5y=413 both equations are true so the easiest way to solve it is by solving the first equation first by saying x=125-y plug this new value of x into the second equation by replacing x 4(125-y) +2.5y=413 solve this equation for y then plug the value of y back into x=125-y to find the value for x

700/2 = 350350 - 25 = 325325 adult tickets700 - 325 = 375375 kids tickets

Let A be the number of adult tickets sold. As 325 tickets in total were sold, the number sold to students was 325 - A. The income from the sale of adult tickets = A x 5 = 5A The income from the sale of student tickets = (325 - A) x 2 = 650 - 2A Total Income = 995 = 5A + 650 - 2A = 3A + 650 3A = 995 - 650 = 345 A = 115, therefore S = 325 - 115 = 210. 115 Adult tickets were sold and 210 Student tickets.

a=# of adult tickets, s=# of student tickets 8a+5s=3475 a+s=500 Solve for s in this equation: s=500-a Now substitute 500-a in for s in the equation 8a+5s=3475: 8a+5(500-a)=3475 8a+2500-5a=3475 3a=975 a=325 ans. There were 325 adult tickets sold.

It depends on the concert. But most of the time no you dont need an adult to go to a concert.

well you must be an 18 or older to bye tickets and if your under 18 you must have an adult with you

A + S = 50 ===> S = 50 - A5A + 3S = 1805A + 3(50 - A) = 1805A + 150 - 3A = 1802A = 30[ A = 15 ][ S = 35 ]=====================Check:5(15) + 3(35) = 75 + 105 = 180 yay!

Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.

x=adult y=student x+y=810 4x+3y=2853 3240-y=2853 y=387 x=423 check: 4*423=1692 3*387=1161 add together 2853 423 adult tickets 387 student tickets

2 adults, 6 students 4 adults, 3 students 6 adults 9 students 4 combinations

$8.50a +$5.50c

Something is wrong with the math here, if you sold each ticket for only a dollar each, you should have at least 500 dollars but you only have 475. I think someone is flagrantly skimming money in your boxoffice.

Adult tickets to the Metropolitan Museum of Art are $25 each but children under 16 get in for free. Students with student ID's get in for $14 and the elderly get in for $18.

Anytime your parents let you. Depending on the concert. But, realistically, you can go to any concert without adult supervision when you are 18 or older.

If it is a 19+ concert you must be 19 or older to enter, adult or not.

Well, 12-50 years old to attend a concert if younger bring an adult or/and ask an adult.

if it is a concert without really bad language,