41 should be in between 14 and 122
using mental math to find the missing numbers. make 8 12345 _ _ _ _ 4 what are the missing numbers Make 6 0 _ _ _ 6 _ _ _ what are the missing numbers
365.
Find the missing number in the series (in red) :2 , 4 , 5, 9, 9 , 16 , 14 , ? , 20 , ….
62
41 should be in between 14 and 122
The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.
412 + 31 = 55 + 32 = 1414 + 33 = 4141 + 34 = 122The next number would be 122 + 35 = 365.
using mental math to find the missing numbers. make 8 12345 _ _ _ _ 4 what are the missing numbers Make 6 0 _ _ _ 6 _ _ _ what are the missing numbers
13168? hmm too short to know for sure. But there is a pattern I found. For the first number the difference from 2 and 0 is 2. So you times the difference by 2 (the number) and then add 1 to get 5. For the second number the difference from 5 and 2 is 3. So you times 3 (the difference) by 5 the number and then subtract 1 to get 14. For the third number the difference from 14 and 5 is 9. So 9 times 14 and then you subtract 4 to get 122. So, for the next number you would take the difference from 122 and 14 which is 108, then times that by 122 and get 13176, then following the pattern of (1, -1, -4) you would subtract 13176 by 8 to get 13168.
365.
Find the missing number in the series (in red) :2 , 4 , 5, 9, 9 , 16 , 14 , ? , 20 , ….
The next number works out as 365
2
62
Let the first of the consecutive numbers be x. So the second number would be x + 2, and the third number would be x + 4. We have: 3x + 4(x + 1) + 5(x + 2) = 122 3x + 4x + 4 + 5x + 10 = 122 12x + 14 = 122 12x + 14 - 14 = 122 - 14 12x = 108 12x/12 = 108/12 x = 9 the first number x + 1 = 9 +1 = 10 the second number x + 2 = 9 + 2 = 11 the third numberCheck:(3*9)+(4*10)+(5*11) =? 122 122 = 122 True