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We have 3 times as many nickles as dimes. Let X equal our number of dimes then 3X equals our number of nickles.

Now multiply these values by the value of the coins they represent.

So we get : 10(X) + 5(3X)=150 cents or $1.50

next : 10X + 15X = 150

25X = 150 Divide both sides of the equation by 25

X = 6 so we have six dimes = 60 cents

we have 3(X) nickels or 3(6) nickels or 18 nickels and 18 times 5 cents = 90 cents

60 cents in dimes plus 90 cents in nickels = $1.50

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Q: Mr Merrill has 3 times as many nickels as dimes The coins have a total value of 1.50 How many of each coin does he have?

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Letx = number of nickels 7x = number of dimes 7x (.10) + x (.05) = 3.75 .7x + .05x = 3.75 .75x = 3.75 x = 3.75/.75 = 5 nickels 7x = 35 dimes

5

1 nickel = 5c 1 dime = 10c If 75c were all nickels then there would be 15 nickels. 2 nickels can then be changed for 1 dime and this can be done 7 times so that the final make up is 1 nickel and 7 dimes. There are thus 8 ways of producing 75c using just nickels and dimes.

7 Quarters= $0.25 times 7= $1.75 10 Dimes= $0.10 times 10= $1.00 10 Nickels= $0.05 times 10= $0.50 17 Pennies= $0.01 times 17= $0.17 So in total you would have $3.42

You just have to take this one step at a time. Start out with the first part:One-third of them were pennies. So of the 24 coins, a third of them were pennies. Multiply 1/3 by 24 and you get eight.One-fourth of them were nickels. 1/4 times 24 is Six.One-sixth of them were dimes. 1/6 times 24 is Four.And the rest were Quarters. Add up the total number of coins you have already (8+6+4=18) and then subtract that from 24. You answer is 24-18=6So, you have:Eight PenniesSix NickelsFour DimesSix Quarters

Only once. You'd need 10 pennies. Using 10 dimes would equal $1. Using 10 nickels would be $0.50. Using 10 quarters would be $2.50.

You almost scared me with this one, but I'll give it a go. Easy ones first: (1) 3 quarters (2) 7 dimes; 1 nickel (3) 15 nickels Then it gets tricky: (4) 2 quarters, 5 nickels (5) 2, quarters, 2 dimes, 1 nickel (6) 1 more time to convert 1 dime into 2 nickels (7) 1 quarter, 10 nickels (8) 1 quarter, 5 dimes (9-12) 4 more times to convert each dime, but 1, into 2 nickels (13-18) 6 more times to convert each dime, but 1, into 2 nickels. Did I miss any? 18 different ways (thank goodness you didn't include pennies!)

There are 10 nickels, 20 dimes and 40 quarters in the cash register. The 10 nickels is 10 x 5 cents or 50 cents. The 20 dimes is 20 x 10 cents or 200 cents. The 40 quarters is 40 x 25 cents or 1000 cents. Converting and adding these, we get $0.50 + $2.00 + $10.00 = $12.50, which is the sum given in the question. Let's work through it. The number of nickels is N, the number of dimes is D and the number of quarters is Q. These are our variables in this problem. We don't know how many of them there are, and their numbers could vary. That's why we call them variables. We might also call them unknowns, too. A nickel is 5 cents, so the value of the nickels is the number of nickels, which is N, times the value of the nickel, which is 5 cents. That's 5N here. A dime is 10 cents, so the value of the dimes is the number of dimes, which is D, times the value of the dime, which is 10 cents. That's 10D here. A quarter is 25 cents, so the value of the quarters is the number of quarters, which is Q, times the value of the quarter, which is 25 cents. That's 25Q here. The sum of the values of the coins was given as $12.50, or 1250 cents, because we are working with coins, whose values are measured in cents. Further, we can write this expression as 5N + 10D + 25Q = 1250 on our way to the answer. Of the last two facts, the first was that there were twice as many dimes as nickels. We could write that as D = 2N because said another way, there are twice the number of dimes as nickels. We might also say that for every nickel, there are 2 dimes, so doubling the number of nickels will give us the number of dimes. The last fact is that there were twice as many quarters as dimes. We could write that as Q = 2D because said another way, thre are twice the number of quarters as dimes. We might also say that for every dime, there are 2 quarters, so doubling the number of dimes will give us the number of quarters. The last two bits of data we have allow us to solve the problem, because the do something special for us. Each bit of data expresses one variable in terms of another. That means we can make substitutions in our expressions for the sum of the values of the coins. Let's put up or original expression, and then do some substitutions. 5N + 10D + 25Q = 1250 This is the original expression. We know that D = 2N, so lets put the 2N in where we see D and expand things a bit. 5N + 10(2N) + 25Q = 1250 5N + 20N + 25Q = 1250 We changed the "look" of the expression, but we didn't change its value. Let's go on. We know that Q = 2D, so lets put that in. 5N + 20N + 25Q = 1250 5N + 20N + 25(2D) = 1250 5N + 20N + 50D = 1250 We're almost there. Remember that D = 2N, and we can substitute that in here. 5N + 20N + 50D = 1250 5N + 20N + 50(2N) = 1250 5N + 20N + 100N = 1250 Groovy! We have substituted variables and now have an expression with only one variable in it! Let's proceed. 5N + 20N + 100N = 1250 125N = 1250 We're close! N = 1250/125 = 10 N = 10 The number of nickels is 10, and because the nickel is 5 cents, the value of these coins is their number times their value, or 10 x 5 cents = 50 cents = $0.50 We were told the number of dimes was twice the number of nickels. This means that since there are 10 nickels, there will 2 x 10 or 20 dimes. And 20 x 10 cents = 200 cents = $2.00 We were also told the number of quarters was twice the number of dimes. This means that since there are 20 dimes, there will be 2 x 20 or 40 quarters. And 40 x 25 cents = 1,000 cents = $10.00 If we add the values of the coins, we should get the $12.50 that we were told was in the register. $0.50 + $2.00 + $10.00 = $12.50 We're in business. The value of each denomination of coins adds up to the given value of all the coins in the register. Piece of cake.

The following denominations of circulating coins were made of 90% silver and 10% copper: > Half dimes, up to 1873 > Dimes, quarters, and half dollars up to 1964 > Dollars up to 1935 These were 40% silver and 60% copper: > Half dollars, 1965-1969. These were 35% silver: > Nickels, mid-1942 to 1945 due to wartime metal shortages. All other nickels are made of copper and nickel. Collectors' versions of quarters, halves, and dollars were also made of 40% silver at various times from 1971 to 1976. Since 1992 special "prestige" versions of dimes, quarters, and halves have been made of 90% silver, and are only available to collectors.

No, the value depends on the purity of silver, which coins you are talking about and the silver spot price. Currently, all US 90% silver coins (quarters, dimes and half dollars dated 1964 and before) are worth in melt value about 21 times face value. The percentage varies if you are talking about 40% silver half dollars (dated 1965-1970) and 35% silver war nickels (nickels dated 1942-1945 with a large mintmark over the Monticello). Of course, if silver were to go back up, they'd be worth more times face value. If silver drops, they'd be worth less than 21 times face value.

7 quarters equals out to $1.75. 5 times equals out to $0.50. 3 nickels equals out to $0.15. 4 pennies equals out to $0.04. All together they would equal $2.44.

105 dimes

When buying antique silver coins you should be looking for silver dimes, quarters, half dollars and silver dollars. These silver coins are reported to be worth many times their face value today. Each of these coins are heavy with 90% silver.

There are 10 dimes in a dollar, so 10 dollars times 10 dimes would equal 100 dimes.

Each quarter has 5 nickels. 5 times 6.