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Q: X to the 2nd power minus 4x over x to the second power minus 16 divided by x to the 2nd power plus 2x minus 24 over x to the 2nd power minus 2x minus 24?

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2x 2x to the second

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If you multiplied all the terms by y2, you could simplify this to -3y3.

1 divided by 25 multiplied by z to the third power

Type this: ((w^2)/(w-6))((w^2-4w-12)/(w^2-3w) Into wolframalpha.com. It will give you the answer (too much for this box).

3 to the power of 1 is 3. 3 to the power of minus 2 is equal to 1 over 3 to the power of 2. 3 to the power of 2 is 9. 3 to the power of 1 times 3 to the power of minus 2 is the same as... 3 divided by 3 to the power of 2. So that gives us 3 divided by 9 which is the same as 1/3.

It is 1 over r squared, or r to the negative second power.

negative 9 over 2

-3/16 since the answer is negative (the second number is larger) and the problem is subtraction you minus the second number from the first then make the answer negative and you have the answer

10 to the power 3 means 10*10*10, or 1000 10 to the power MINUS 3 means 1 over 10 to the power 3, so 1/1000.

3^-1 = 1 over (3 to the power of 1) = 1/3, one third. a minus power is the same as a normal power but with a 1 above it.

By factoring I get x-3 divided by x+3

1

Actually five over six minus one over eight can be placed as five divided by six minus one divided by 8, which looks like this: 5/6-1/8 5 divide 6-1 = 5 divide 5 = 1 1 divide by 8 =1 over 8 Ans: 1 over 8

That's a Gaussian distribution.

The quadric equation is: negative b plus or minus the square root of b squared minus 4ac all over(divided by) 2a

dont ask stupid question

it is 1/16777216 because you just do 16 to the power of 6 then put a one over it

28 divided by 7 is 4. SO 63 minus 4 = 59

(2^5)/2 - (2^(3/2)) = 12

answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}

2/4 raised to the second power equals 0.25

It is: m6 divided by m10 = m-4

34 - 64/4 = 34 - 16 = 18 (remember that division takes precedence over subtraction).

3n^4 divided by 3n^3 = n