Best Answer

Four?

Factoring

Graphing

Quadratic Equation

Completing the Square

There may be more, but there's at least four.

Q: Name four ways to solve a quadraic equation?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

(4/9) x = That's not an equation. If there were a number after the 'equals' sign, then we could calculate the value of 'x'. But as it is, there's no question there, so there's nothing to solve.

Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.

Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A

1. Quadratics should always contain a set of numbers inconjuction with letters (x usually). 2. Quadratics are always in the form ax2 + bx + c. Where a,b and c are constants and x is a variable. 'a' must always equal '0'. 3. The total equation must never equal '0'. 4. To solve quadratics, you DO NOT factorise. 5. To solve quadratics, use the formula x=a, therefore, b=c. 6. The word 'quadratics' literally means four. This in term means that there are four ways you can solve for the answer of the equation.

In your question you have two equations. They are... m + n = 1000 Equation (1) 0.05 + 0.06n = 57 Equation (2) It is a rule of thumb that if you have two equations and two unknowns (the unknowns in this case are "m" and "n") you can solve for them. Also remember if you have three euqations and three unknowns you can solve for them.. four euqations four unknowns... etc.. Ok first take the 2nd equation and solve for "n" 0.05 + 0.06n = 57 0.06n = 56.95 n= 949 and 1/6 Now that you have "n" you can put it into the 1st euqation and solve for "m" m + (5695/6) = 1000 m = 50 and 5/6 Therefore you answers are... n=949.16666 or 949 1/6 or 5695/6 m=50.83333 or 50 5/6 or 305/6

Related questions

Because this equation has four variables, it would require four unique equations involving only these four variables to solve.

There are four steps in an algebraic elimination problem. These steps are: to find a variable with equal or opposite coefficients, if equal then subtract the equations but if opposite then add, solve one variable equation left, and then substitute known variable into other equation and solve. hi

SRY THE Q IS HOW CAN YOU WRITE AND SOLVE: Twenty four is three less than one-third of a number.?

(4/9) x = That's not an equation. If there were a number after the 'equals' sign, then we could calculate the value of 'x'. But as it is, there's no question there, so there's nothing to solve.

That depends on the equation; you need to give some examples of what you want factored. There are four steps to solving an equation. Should any other factors be accounted for when solving an equation? Should any factors be accounted for when explaining how to solve an equation?

Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.

There is no special name for this.

each of the four regions created on the coordinate plane by the x- and y-axes.

Create a matrix of the coefficients of each equation. The solutions to the equations should make up the rightmost column of the matrix. Then, row reduce the matrix until you are able to rewrite the equations and solve them. The matrix should be a 4x5 matrix (4 rows and 5 columns) for four equations with four variables. This is known as a system of equations.

4/7

Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A

Write an equation for the perimeter, and solve it. Remember that the perimeter is the sum of all four sides.