A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1
Add the two equations: A*sin(x) + B*sin(x) = 2
(A+B)*sin(x) = 2
sin(x) = 2/(A+B)
x = arcsin{2/(A+B)}
That is the main solution. There may be others: depending on the range for x.
For any sort of calculation, Wolfram|Alpha is very helpful. If you have a calculation-based question, or if you need facts about food, careers, stars, or any sort of numerical data, Wolfram|Alpha is likely your best first stop. Also, if you have a math or physics problem, it's a great place to try to find a solution.
9410 + 5490 = 14900
No. But sin2a equals 1 minus cos2a ... and ... cos2a equals 1 minus sin2a
You can obtain actual graphs of algebraic equations at the Wolfram Alpha website. wolframalpha.com
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For any sort of calculation, Wolfram|Alpha is very helpful. If you have a calculation-based question, or if you need facts about food, careers, stars, or any sort of numerical data, Wolfram|Alpha is likely your best first stop. Also, if you have a math or physics problem, it's a great place to try to find a solution.
You should supply more information.
9410 + 5490 = 14900
Alpha radiation can be stopped by pretty much anything: 5 cm of air, a piece of paper, skin, etc. Alpha particles are not dangerous unless inhaled, so skin is a safe solution.
According to Wolfram Alpha, (1/2) (9 plus or minus i times the square root of 39) Since these numbers are complex, it means there is no solution with real numbers for this problem.
It's not. The coefficient of static friction is only equal to the tangent of the angle of incline at the maximum angle before the object begins to slide. At this point static friction equals the component of the weight along the incline (weight X sin alpha). Static friction is given by the coefficient of static friction times the normal force (weight X cos alpha) fs = us N = us mg cos(alpha) Wx =mg sin(alpha) fs = Wx us mg cos(alpha) = mg sin(alpha) us = [sin(alpha)] / [cos(alpha)] = tan(alpha) Similarly, the coefficient of kinetic friction equals the tangent of the angle of incline only if the object is sliding down the incline at constant velocity (net force equals zero). If the object is accelerating along the incline (make this the x axis): Fnet, x = Wx - f max = mg sin(alpha) - uk mg cos(alpha) uk = [g sin(alpha) - ax] / [g cos(alpha)]
No. But sin2a equals 1 minus cos2a ... and ... cos2a equals 1 minus sin2a
If you need to ask, you probably can't."Alpha hydroxy" is a marketing term that refers to a carboxylic acid which has a hydroxyl group on the carbon adjacent to the acidic carbon.If you can get your hands on some alpha hydroxy acids, you could dissolve them and make an "alpha-hydroxy" solution. But do you really want to put something you mixed up at home using a compound with the term "acid" in it on your face? There's a REASON the marketing term leaves out the "acid" part.Some fairly common and relatively innocuous alpha hydroxy acids are citric acid and lactic acid, if you're bound and determined to do this. In fact, lemon juice is ALREADY an alpha hydroxy solution; if you want something you can make at home.
Alpha block refers to the suppression or reduction of alpha brain waves when an individual is engaged in a cognitive task or facing a stimulus. This phenomenon can be measured using electroencephalography (EEG) and is associated with increased mental alertness and concentration.
I'm going to let Paul A. Tipler (Aka my 50lb physics textbook) answer this one.First to explain why I (rotational inertia) is in the equation.T (not period, but tao, or torque) is defined as F x RBy Newton's second law F = ma, in a rotating body a = alpha x RF = m(alpha)Rif you multiply both sides by RF x R = m(alpha)R2Recall F x R is TT = m(alpha)R2Sum the torques in the entire bodySigma(T) = Sigma(mR2(alpha))Therefore I is defined as Sigma(mR2), or for a continuous object(a disk) I = the Integral of (R2dm)Therefore, Sigma(T) = I x alphaThis is analogous with Newton's second law: F = ma. Where in rotation F --> T, m --> I, a --> alpha
No, there are no roms for Pokemon Omega Ruby and Alpha Sapphire currently nor a working 3DS emulator. (They are also incompatible with the Desmume emulator.)
The answer i found out, is supposed to be because the Alpha PAL8045 is too heavy but all answers i found online do not note this as a problem.