On a graph of speed versus time, where time is plotted along the horizontal (X) axis and speed along the vertical (Y) axis: -- constant speed (zero acceleration) produces a straight, horizontal line; -- constant acceleration produces a straight, sloped line; the slope of the line is equal to the acceleration; -- if the acceleration is positive, the line slopes up to the right (speed increases as time increases); -- if the acceleration is negative, the line slopes down to the right (speed decreases as time increases).
By showing a straight line.
velocity is nothing but speed of a body in the given direction. suppose if body is moving with constant velocity then VT graph will be parallel to the X -axis, if not then the VT graph is not parallel to the X-axis it means then object is moving with different velocity or it has its dierection or both velocity and aswell as direction.
The object's instantaneous acceleration is (8t - 8) at any time.We can't calculate the average acceleration, because you haven't defined a periodof time over which to average it. We need the start and finish times in order tofind an average.
there is no VI on the us map, but there is VA and VT which means Vermont (VT) and Virginia (VA).
This method assumes a constant speed, and can be used if there is an object travelling from Sun to Earth, or from Earth to Sun (at constant speed, of course), and you know both the speed and the time it takes. It doesn't seem to be a very practical method in this case. Note that if you throw an object toward the Sun, it will go faster and faster, due to the Sun's gravitation, so you wouldn't have a constant speed. You can use the equivalent formula with integrals, of course.
cosine @-= t / vt
You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT
Vt=w*r where; * is multiply Vt is tangential velocity w is omega(angular mometum) r is radius
velocity is nothing but speed of a body in the given direction. suppose if body is moving with constant velocity then VT graph will be parallel to the X -axis, if not then the VT graph is not parallel to the X-axis it means then object is moving with different velocity or it has its dierection or both velocity and aswell as direction.
Rd= Vt*c/I Vt=KT/q, K=Boltzmann constant C= constant 2 for si 1 for Ge I current through the diode
If the velocity is constant then it is enough to use the equation, s = vt. S- the displacement, t - time elapsed and v the uniform or constant velocity. If velocity changes, then acceleration is there in action. Hence the final velocity after time t will be given as v = u + at.
It depends on what aspect of constant velocity you are talking about. Since the velocity is not changing, one valid equation is: V = [number] At the same time, acceleration is zero, so another equation is: A = 0 If "p" is position and p1 is the original position and p2 is the current position after tine lapse "t," then: p2 = p1 + Vt
To find the acceleration if the time is not given, you will need to know the velocity and the distance. Then, use this equation: d = vt + (1/2)at2 to solve the problem by plugging in your numbers for the distance and the velocity.
Where the law is concerned - ANYTHING is possible. Realistically, they might simply place a warrant on file for you and if you appear again in VT, and come to the attention of the authorities, you will just be arrested then.
did vtu announce grace marks for the subject graph theory 4th sem(2006 scheme) exam was held on june 24th 2013
A car moving at a constant speed (no acceleration) will be defined as V= D/T where V= velocity, D= distance, and T= time. rearranging you could also see: D= VT or T=D/V.
There are about 20 miles between Bristol VT and Bridport VT.
ag = GM/d2. ag is the gravitational acceleration; G is the gravitational constant; M is the mass of the primary body (e.g. planet); d is the distance between the centres of mass of the primary and secondary bodies.