There are 21 three-legged cows and 27 chickens on the farm.
Let us say the number of cows = A and the number of chickens is B.
The equation for heads is:
A+B = 48
The equation for legs is:
3A + 2B = 117 (because a cow has 3 legs and a chicken has 2 legs in this question)
We can rearrange the equation for heads as follows:
A+B = 48
B = 48-A
Now we can replace B in the equation for legs with 48-A as follows:
3A + 2(48-A) = 117
...and solve:
3A + 96 - 2A = 117
A + 96 = 117
A = 21
So we know there are 21 three-legged cows and from earlier, B = 48-A, so B = 48-21 = 27. Therefore there are 27 chickens.
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
There are 42 chickens in the farm.
85 chickens
there are 36 horses and 23 chickens.........
There are 61 horses and 10 chickens on the farm.
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
There are 42 chickens in the farm.
85 chickens
there are 36 horses and 23 chickens.........
There are 61 horses and 10 chickens on the farm.
27
Suppose there are x chickens and y cows Then heads => x + y = 64 And Legs => 2x + 3y = 147 2*Heads: 2x +2y = 128 Subtract from Legs: 19 = y Substitute in Heads: x = 45 Answer: 45 chickens.
94 three legged cows and 25 chickens.
50 horses and 10 chickens
This is not possible
If all were horses there would be 428 legs. The shortfall of 36 legs represents 18 chickens so there are 89 horses.
7 cows and 11 chickens. Cows have 4 legs. Chickens have 2 legs. (4 legs)(7 cows) + (2 legs)(11 chickens) = 50 legs. 7 cow heads = 11 chicken heads = 18 heads.