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let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x)

(x-3)=(72-2x).

3x-3=72.

3x=75

x=25.

36-25=11.

Answer: the smaller number is 11.

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Q: One integer is 3 more than twice another integer if the sum of the two integers is 36 what is the smaller integer?
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