Q: One kilograms meters over seconds squared?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Just over 13.9 m2

2

D = V0 t + 1/2 A t250 = 15 + 1/2 (4) t235 = 2 t2t = sqrt(35/2) = sqrt(17.5) = 4.183 seconds (rounded)

No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.

In general, the acceleration during that time interval could vary considerably. However, we can calculate the average acceleration during the interval. The change in speed is 20 meters per second - 5 meters per second = 15 meters per second, and this change in speed occurs over a 3 second interval. Thus the average change in speed over this interval is 15 meters per second/ 3 seconds = 5 meters per second per second = 5 meters/second2

Related questions

.281 meters

Just over 13.9 m2

Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)

Ten meters per second squared, or ten meters per second per second is the term used for acceleration. In this case it is referring to the acceleration caused by gravity. If you were on the top of a steep cliff and threw a ball over the side, it would accelerate at 10 meters per second squared. So after 10 meters is would be going 20 meters a second.

One over A squared or A to the negative 2.

Yes, very big they can get up to 6 meters which is 20 feet feet and over 2,000 kilograms

2.191m/s if 4.382 is in metres

2

It is 0.1 metre per second-squared.

D = V0 t + 1/2 A t250 = 15 + 1/2 (4) t235 = 2 t2t = sqrt(35/2) = sqrt(17.5) = 4.183 seconds (rounded)

Yes, very big they can get up to 6 meters which is 20 feet feet and over 2,000 kilograms

No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.