"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
Eleven times one divided by eleven (1/11) is one.
Eleven cannot be squared, unless by a mixed number, because nothing times four equals eleven.
38 and 190
5 and 2
Only 1 and 59 - it's a prime number.
nothing stupid i mean what a question
n3 + 11*n
three times a number decreased by eleven
12 and 56
The number is 231.
eleven times eleven equals one hundred and twenty one.
They are 7 and 5.
The sum of the numbers is 240. If one number is 5 times as big as the other then 240 must be divided by 6. 240/6 = 40. The smaller number must be this while the larger number is 5 times the size. Small number = 40 Larger number = 40 * 5 = 200
3x + 11
The only numbers that multiply to get a product of 39 are 1 and 39, or 3 and 13.
n + 11n = 84
You see how many times the two digit number goes into the first two numbers then you will take them away and then you will get the third number and put it on the end of your answer then you will see how many times your two digit number goes into your new number and then you will get your answer. And by the way I am eleven and I am still in primary school so you should really know it. I can divide a two digit by a seventeen digit number and that ins easy peasy.
If your number is 4 times ?, and the sum is 40, your problem would be 40 divided by 4. You'd get 10.
12 and 18
The number one appears 5 times on a 12 hour clock face. One, ten, eleven (twice) and twelve o'clock.