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Perimeter of PAKE = 42 units

so PA + AK + KE + EP = 42 units

But, since PAKE is a parallelogram, PA = KE and EP = AK

which gives KE + AK + KE + AK = 42 units

or AK + KE = 42/2 = 21 units.

Now, perimeter of AKE = 33 units

that is AK + KE + EA = 33 units

But AK + KE = 21 units so 21 + EA = 33 units

so EA = 33 - 21 = 12 units.

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Q: Parallelogram PAKE has diagonals PK and AE intersect at R perimeter of triangle AKE equals 33 perimeter PAKE equals 42 length of AE is?
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