Let x be the miles that Pete traveled on the second day, so he traveled 1.5x miles on the first day. So we have:
1.5x + x = 1,380
2.5x = 1,380
2.5x/2.5 = 1,380/2.5
x = 552
1.5x = 1.5 x 552
1.5x = 828
Thus, Pete traveled 828 miles on the first day.
On day 1 he traveled 428 miles and on day two he traveled 668 miles
1/4/2 = 1/8 mile per second 1/8 mile per second times 60 seconds per minute = 7.5 miles per minute 7.5 miles per minute x 60 minutes per hour = 450 miles per hour
50 mph, 40+60=100/2=50, assuming you use the same route.
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Divide the distance by the speed.
On day 1 he traveled 428 miles and on day two he traveled 668 miles
12
yes if u traveled 300mph
How fast you are going and how far you have traveled.
Michigan, Indiana & Illinois.
The second drive.....
Normally the second removable drive, A = first removable or floppy drive, if a second floppy drive is installed it is drive B. First hard disk is Drive C, second Hard disk is Drive D, etc. You can also map the drive letters to the virtual network connections, so that Drive P could be used as a network connection.
d = r x t (A+)
d = r x t (A+)
About 2,490-2,688 miles depends on route traveled.
You would drive through Canada.Canada.
Distance equals Rate times Time.