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22 x 71

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Q: Prime factorization of 28 using exponents?
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What are the factors and prime factors of 112?

112 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 10 factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112.The factor pairs of 112 are 1 x 112, 2 x 56, 4 x 28, 7 x 16, and 8 x 14.The proper factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, and 56 or,if the definition you are using excludes 1, they are 2, 4, 7, 8, 14, 16, 28, and 56.The prime factors of are 2, 2, 2, 2, and 7.Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors (listing each prime factor only once) of 112 are 2 and 7.The prime factorization of 112 is 2 x 2 x 2 x 2 x 7 or, in index form (in other words, using exponents), 24 x 7.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple of a single number because "common" refers to factors or multiples that two or more numbers have in common.Factor tree:112/\2 x 56/\8 x 7/\2 x 4/\2 x 2And you are going to want to circle the prime numbers which would be four 2's and one 7. Then after you are done circling the prime numbers, you write the prime factorization as 2x2x2x2x7 = 24 x 7.The prime factors of 112 are 2 x 2 x 2 x 2 x 7.


What is the GCF of 14m and 21m?

GCF(28, 21) = 7 Steps: Prime factorization of the numbers: 28 = 2 × 2 × 7 21 = 3 × 7 GCF(28, 21) = 7


What is the prime factorization of 252 in exponential form?

252 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 18 factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, and 252.The factor pairs of 252 are 1 x 252, 2 x 126, 3 x 84, 4 x 63, 6 x 42, 7 x 36, 9 x 28, 12 x 21, and 14 x 18.The proper factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, and 126 or,if the definition you are using excludes 1, they are 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, and 126.The prime factors of 252 are 2, 2, 3, 3, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 252 are 2, 3, and 7.The prime factorization of 252 are 2 x 2 x 3 x 3 x 7 or, in exponential form, 22 x 32 x 7.


What is the GCF of 28 35 and 56?

7Prime Factorization of:28 = 2 * 2 * 735 = …………..7 * 556 = 2 * 2 * 7……..* 2===============GCF=…………..7


What is the HCF of 8 and 28?

To find the HCF of two numbers, you need to express them in their prime factors: 8 = 2x2x2 28 = 2x2x7 The next step is to identify any common prime factors. In this case both numbers have two 2s as prime factors. Multiply these together and you get: 2x2 = 4 Thus 4 is the hcf of 8 and 28.

Related questions

What is the prime factorization for 256 using exponents?

256 = 28.


What is prime factorization of 28 using exponents?

22 x 7 = 28


How do you write a prime factorization of 28 using exponents?

22 x 7 = 28


What is the prime factorization of 768 using exponents?

768 = 28 x 31


What is the prime factorization using exponents of 28?

28 = 22 x 71


What is the prime factorization of four million using exponents?

28 x 56 = 4,000,000


What is the Prime factorization exponents of 28?

28 = 22 x 71


What are the prime factorization with exponents of 28?

22 x 7 = 28


What is factorization of 28 using exponents?

22 x 7 = 28


What is the prime factorization of 28 with exponents?

The prime factorization is: 22 x 7


What is the prime factors using exponents for 28?

22 x 7 = 28


Do a prime factorization for 28 using factor tree?

28 14,2 7,2,2