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Q: Quotient and remainder of 3X4 plus 2X3 minus X2 minus x minus 6 divided by X2 plus 1?

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4x2 + 6x - 3 (with no remainder)

The dividend. Divident / Divisor = Quotient (plus remainder)

6x3+29x2-40x-42 divided by 6x+5 Quotient: x2+4x-10 Remainder: 8

The quotient works out as: x^2+2x+4 and there is a remainder of -3

x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3

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3x

Quotient: 2x3-x2-14x+42 Remainder: -131 over (x+3)

That depends on whether or not 2x is a plus or a minus

Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7

Answer is x2 -6x+14 with remainder 2

Plus

To find the number, multiply the divisor and quotient, then add the remainder. 9 (divisor) times 6 is 54. 54 plus 7 is 61. The number is 61.

Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7

Dividend: 6x^3 +29^2 -40x -42 Divisor: 6x +5 Quotient: x^2 +4x -10 Remainder: 8

2x^3 - 3x^2 + 4x - 3

2x2-4x+5 divided by x-1 Quotient: 2x-2 Remainder: 3

The remainder is 0.

A plus number.

x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2

x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]

Dividend: 4x^4 -x^3 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7

Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12

8*7 = 56, plus the remainder.

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