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The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.

Q: Rationalize 5 over square root of 6?

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You cannot. The square root of 5 is irrational.

The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5

I think it is the square root of 5.

5 times the square root of two over 3 times the square root of two equals 5/3

5

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You cannot. The square root of 5 is irrational.

0.625

If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578

Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5

a+ square root of b has a conjugate a- square root of b and this is used rationalize the denominator when it contains a square root. If we want to multiply 5 x square root of 10 by something to get rid of the radical you can multiply it by square root of 10. But if we look at 5x( square root of 10 as ) 0+ 5x square root of 10 then the conjugate would be -5x square root of 10

b over the square root of 5 The square root of 5b squared is 5b, and the simplified form of the square root of 125 is 5 root 5. The 5s then cancel out leaving b over the square root of 5.

The square root needs to be removed from the bottom. To do this multiply the numberater and denominator by the square root of 5. 125xsquare root of five over 5 25square root of 5 is the simplest answer.

The square root of fraction 20 over 25: = √20 ...√25 = √4(5) ......5 = 2√5 .....5 or 2 square root of 5 over 5

I think it is the square root of 5.

5 times the square root of two over 3 times the square root of two equals 5/3

5

Square root of 40 approximately = 6.324555325 / square root of 40 = 0.790569415