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5r x 6t = 30rt
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What are x and y if 5 x y 40 are in a Geometric Progression?
For Geometric Progression #1 = a = 5 #2 = ar = x #3 = ar^2 = y #4 = ar^3 = 40 We need to find 'r' To do this ,divide #4 by #1 , hence ar^3 / a = 40 / 5 Hence r^3 = 8 (Notice the 'a' cancels down to leave 'r^3' Cube root both sides Hence r = 2 When r = 2 #2 = ar = 5 X 2 = 10 = x #3 = ar%2 - 5 x 2^2 = 5 x 4 = 20 = y So the geometric progression is 5,x,y,40 = 5,10,20,40
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1
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X-HY NSM8 6&3&2Q&P 520# 7WQ8 or Q@M=X QYC7R9S X@R675%@KM 5R#6J%8 65NP@
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X= -2
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What are x and y if 5 x y 40 are in a Geometric Progression?
For Geometric Progression #1 = a = 5 #2 = ar = x #3 = ar^2 = y #4 = ar^3 = 40 We need to find 'r' To do this ,divide #4 by #1 , hence ar^3 / a = 40 / 5 Hence r^3 = 8 (Notice the 'a' cancels down to leave 'r^3' Cube root both sides Hence r = 2 When r = 2 #2 = ar = 5 X 2 = 10 = x #3 = ar%2 - 5 x 2^2 = 5 x 4 = 20 = y So the geometric progression is 5,x,y,40 = 5,10,20,40
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