3q + 5 + 2q + 5 = 65
5q + 10 = 65
5q = 55
q = 11
Check it.
33 + 5 + 22 + 5 = 65
It checks.
The above set of three terms cannot be simplified.
Q=2
5*(2q + 5r)
7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)
6p + 12q + 18r = 6 (p + 2q + 3r)
Without an equality sign the given expression can't be considered to be an equation.
simply add the like terms: 4p -3p +2q -2q = p
3
-q-11=2q+4 you would subtract 4 from both sides 4 and -4 cancel out and -11-4= -15 then you get -q-15=2q then you would add Q(1) to both sides (-q and q cancel out) then u get -15=3q thn u divide 3 to both sides (3 and 3 become q) then u get q=-5
Let f(X)=2X2+6X+3 So f(-p)=f(2q) or 2p2-6p+3=8q2+12q+3 or p2-3p=4q2+6q or p2-4q2=3p+6q or (p+2q)(p-2q)=3(p+2q) so p-2q=3
16
The above set of three terms cannot be simplified.
-(b + c - p - 2q)(b + c + p + 2q)
4p+7q
It's an equation and q = 6
Q=2
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0