answersLogoWhite

0

Simplify and solve this equation for q 3q plus 5 plus 2q 5 65?

Updated: 4/28/2022
User Avatar

DeniseJackfb2296

Lvl 1
8y ago

Best Answer

3q + 5 + 2q + 5 = 65

5q + 10 = 65

5q = 55

q = 11

Check it.

33 + 5 + 22 + 5 = 65

It checks.

User Avatar

Wiki User

8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Simplify and solve this equation for q 3q plus 5 plus 2q 5 65?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Equation for q 3q plus 5 plus 2q-565?

Without an equality sign the given expression can't be considered to be an equation.


What is the answer to 4p plus 2q-3p-2q?

simply add the like terms: 4p -3p +2q -2q = p


What is 1p plus q-p plus 2q equals?

3


How do you solve the equation -q-11 equals 2q plus 4?

-q-11=2q+4 you would subtract 4 from both sides 4 and -4 cancel out and -11-4= -15 then you get -q-15=2q then you would add Q(1) to both sides (-q and q cancel out) then u get -15=3q thn u divide 3 to both sides (3 and 3 become q) then u get q=-5


2x to the power of 2 plus 6x plus 3 has the same remainder when divided by x plus p or by x-2q where p is unequal to -2q Find the value of p-2q?

Let f(X)=2X2+6X+3 So f(-p)=f(2q) or 2p2-6p+3=8q2+12q+3 or p2-3p=4q2+6q or p2-4q2=3p+6q or (p+2q)(p-2q)=3(p+2q) so p-2q=3


How do you solve this problem 2q equals -14?

16


Simplify 2q 4r 2?

The above set of three terms cannot be simplified.


What are the factors of p2 plus 4pq plus 4q2-b2-2bc-c2?

-(b + c - p - 2q)(b + c + p + 2q)


What is p plus 3p plus 2q plus 5q?

4p+7q


What is 18-2q equals 4?

It's an equation and q = 6


Q plus 7 equals 2q plus 5?

Q=2


What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?

Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0