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# Solution for tan x plus cot x divided by sec x csc x?

Wiki User

2009-10-16 15:28:19

(tan x + cot x)/sec x . csc x

The key to solve this question is to turn tan x, cot x, sec x, csc x into the simpler form.

Remember that tan x = sin x / cos x, cot x = 1/tan x, sec x = 1/cos x, csc x = 1/sin x

The solution is:

[(sin x / cos x)+(cos x / sin x)] / (1/cos x . 1/sin x)

[(sin x . sin x + cos x . cos x) / (sin x . cos x)] (1/sin x cos x)

[(sin x . sin x + cos x . cos x) / (sin x . cos x)] (sin x . cos x)

then

sin x. sin x + cos x . cos x

sin2x+cos2x

=1

Wiki User

2009-10-16 15:28:19
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