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Solve 16t2 plus vt -S equals 0?

Updated: 9/15/2023
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16t2 + vt - S = 0 This is in the general form of the quadratic equation, and the general quadratic solution can be applied directly. t = [ (-v) plus or minus the square root of (v2 + 64S) ] all divided by 32.

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Q: Solve 16t2 plus vt -S equals 0?
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What is this S equals -10t2 plus vt plus k?

S equals -10t2 plus vt plus k This is one of the three formulae for motion. The standard form is S = ut + 1/2ft2. S = distance, u = initial velocity, f = acceleration, t = time, k is unknown. The equation in the question could thus be written, S = ut - 10t2 +k. This would imply that the acceleration is -10.


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By the Way, guys, this is based on the equation H= -16t2+vt+s


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Related questions

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S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v


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S equals -10t2 plus vt plus k This is one of the three formulae for motion. The standard form is S = ut + 1/2ft2. S = distance, u = initial velocity, f = acceleration, t = time, k is unknown. The equation in the question could thus be written, S = ut - 10t2 +k. This would imply that the acceleration is -10.


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By the Way, guys, this is based on the equation H= -16t2+vt+s


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