Math and Arithmetic

# Solve 7-24i complex number?

That is a complex number in simplest form. There is nothing to solve.

That is a complex number in simplest form. There is nothing to solve.

That is a complex number in simplest form. There is nothing to solve.

That is a complex number in simplest form. There is nothing to solve.

🙏
0
🤨
1
😮
0
😂
0

That is a complex number in simplest form. There is nothing to solve.

🙏
0
🤨
0
😮
0
😂
0

## Related Questions

The ratio of two quantities need not itself be a rational number - it can be a complex number.

scientific method can be adopted to solve complex problem

For ANY complex problem that was ever solved, somebody helped solve it.

If the discriminant - the part under the radical sign in the quadratic formula - is negative, then the result is complex, it is as simple as that. You can't convert a complex number to a real number. If a particular problem requires only real-number solutions, then - if the formula gives complex numbers - you can state that there is no solution.

A complex math problem is one that is hard to solve.

See the answer to the related question: 'How do you solve the power of an imaginary number?' (Link below)

That depends a lot on what you want to solve. In general, you can do quite a lot by simply considering the complex number like any polynomial, and remembering that i2 = -1. For example, to add two complex numbers, you simply add the real and the imaginary part of both numbers.

See related link. Gerolamo Cardano, an Italian mathematician, used the concept of complex numbers around 1545 to solve some equations.

It is not always better.Although quadratic equations always have solutions in the complex system, complex solutions might not always make any sense. In such circumstances, sticking to the real number system makes more sense that trying to evaluate an impossible solution in the complex field.

can solve complex calulations quickly which takes a long time to solve manuall

The conjugate of a complex number is the same number (but the imaginary part has opposite sign). e.g.: A=[5i - 2] --&gt; A*=[-5i - 2] Graphically, as you change the sign, you also change the direction of that vector. The conjugate it's used to solve operations with complex numbers. When a complex number is multiplied by its conjugate, the product is a real number. e.g.: 5/(2-i) --&gt; then you multiply and divide by the complex conjugate (2+i) and get the following: 5(2+i)/(2-i)(2+i)=(10+5i)/5=2+i

How did you solve the most complex math problem on the page? A good psychologist can help him work out his most complex family issues.

You can use the atomic number. It will solve your problem.

Thinking through lots of ways to solve a puzzle

you can use it by writing out the complex into a division problem then improper fraction

The absolute value of a complex number is the magnitude of the number, which is found from sqrt(a&Acirc;&sup2; + b&Acirc;&sup2;) for the complex number a + bi

That depends what is the problem given, and what you want to solve. You may want to read an introductory article on complex numbers, to learn how you add them, multiply them, etc.That depends what is the problem given, and what you want to solve. You may want to read an introductory article on complex numbers, to learn how you add them, multiply them, etc.That depends what is the problem given, and what you want to solve. You may want to read an introductory article on complex numbers, to learn how you add them, multiply them, etc.That depends what is the problem given, and what you want to solve. You may want to read an introductory article on complex numbers, to learn how you add them, multiply them, etc.

You get a complex number unless the real number happens to be 0 or 1.

Yes. And since Real numbers are a subset of complex numbers, a complex number can also be a pure real.Another AnswerYes, for example: (0 + j5) is a complex number, whose 'real' number is zero.

ax2 + bx + c = 0 , find the value of x . b2-4ac&gt;o x is real (2 different values will solve) b2-4ac=o -&gt; a double root (a single real number will solve it) x=real numbers. b2-4ac&lt;0 x= two complex number roots (either pure imaginary or a complex number with real and imaginary components)

No. A complex number is a number that has both a real part and an imaginary part. Technically, a pure imaginary number ... which has no real part ... is not a complex number.

Graphically, the conjugate of a complex number is its reflection on the real axis.

IF they are math related, write appropriate equations and then apply math rules to solve the equations.