7w=122 122/7= 17.43 w=17.43
127w = 847w/7 = 84/7w = 12
56w2 + 17w - 3 = 56w2 + 24w - 7w - 3 = 8w(7w + 3) - 1(7w + 3) = (7w + 3)(8w - 1)
7W + 4 - 3W = 15gather the w's together4W + 4 = 15subtract 4 from each side4W = 11divide each sides integers by 4W = 11/4================checks
7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
I understand this equation to be 7w = 42. The principle we use for solving equations like this one is that we can do the same thing to both sides of the equation and the equation will still be _true_. We want the 'w' by itself. This implies ridding the left side of the 7. We can turn it into a one (1) by dividing it by 7. But if we do that to the left side of the equation then we must also do that to the right side. 7w/7 = 42/7 1w = 6 or w = 6, the result.
25y2 - 49w2 = (5y)2 - (7w)2 = (5y - 7w)(5y + 7w)
(5y + 7w)(5y - 7w)
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
56w2-17w-3 = (8w+1)(7w-3) Using the quadratic equation formula helps.
121 is the answer
How do you solve 4y plus x equals 8
7w - 4w - 6w = (7 - 4 - 6)w = -3w
3w + 4e + 7w - e3 = 10w - e
a equals 5
You can't solve a formula with no equals sign
Not enough information to solve
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.