a is the number which is to be multiplied to x and b then once you do that your outcome should come to what c equals which should be the variable in the equation. the reason i can answer this question is because I'm learning this in math right now and I'm in 8th grade.
It is a straight line with gradient -A/B and intercept C/B.
ax + b = 15 or ax + b = -15
a function
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
It is: 3x2+6x-11 = 0
It is a straight line with gradient -A/B and intercept C/B.
Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)
ax + b = 15 or ax + b = -15
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
a function
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
A linear equation.
x = -c/(a+b), provided a+b is not 0
x = (d-a)/(a-c)
It is: 3x2+6x-11 = 0
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
The first step in solving a quadratic equation of the form ((ax + b)^2 = c) is to take the square root of both sides to eliminate the square. This gives you two possible equations: (ax + b = \sqrt{c}) and (ax + b = -\sqrt{c}). From there, you can isolate (ax) and solve for (x) by subtracting (b) and then dividing by (a).