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Let's talk this out and see if we can work it out.
The sum of the first N odd integers means,
1+3+5+7+9+11+...
Where N is how many odd numbers we're adding.
Let's choose numbers for N, and see if we can find a pattern.
N=1 --> 1
(sum of the first odd integer)
N=2 --> 1 + 3 = 4
(sum of the first 2 odd integers)
N=3 --> 1 + 3 + 5 = 9
(sum of the first 3 odd integers)
N=4 --> 1 + 3 + 5 + 7 = 16
Do you notice a pattern yet? Take a look at when N = 2, what is the sum? That's right, 4!
and when N = 3... the sum is 9.
N = 4 the sum is 16....
I see a pattern, do you?
Answer: If you don't, you'll notice that the sum of the first N odd integers is always = N2
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Three odd consecutive integers whose sum is 176?
First of all, the sum of 3 odd numbers always equals an odd number and 176 is even so this is NOT possible.If you did not know this you could let n be the first odd number, n+2 is the next and n+4 is the third.Add them up and we have n+n+2+n+4=176 or3n+6=176 so3n=170Now you see that 170 is NOT divisible by 3 so ONCE again you see that there is NO solution to this problem. That is to say, there are NOT 3 odd consecutive integers whose sum is 176.
How do you find the sum of the first thirty odd integers?
The arithmetic sequence of odd integers is 1, 3, 5, 7, 9, ... where the common difference is 2. The sum of the first thirty odd integers can be found by using the sum formula such as: Sn = n/2[2a1 + (n - 1)d], where a1 = 1, n = 30, and d = 2. So, S30 = (30/2)[(2)(1) + (30 - 1)(2)] = (15)[2 + (29)(2)] = (15)(60) = 900
Why is the sum of 2 consecutive integers always an odd number?
The sum of two even numbers is always an even number. The sum of two odd numbers is always an even number.The sum of an even number and an odd number is always an odd number.Because integers alternate between even and odd, adding two consecutive integers will always result the sum of an odd number and an even number, which, as stated above, will always be an odd number.Another way to look at it:An even number is divisible by 2, therefore, 2*n (where n is an integer) is always an even number.2*n+1 would be the next number after 2*n (so 2*n & 2*n+1 are consecutive integers).If we add these numbers together, we get 4*n+1 = 2(2*n)+1. Since 2(2*n) is an even number, adding 1 makes it an odd number._________________________________________________________________________I'm not going to but in or anything, seriously that was a good answer
What is the sum of the first 22 odd numbers?
The sum of a sequence is given by sum = n/2(2a + (n-1)d) where: n = how many a = first number of sequence d = difference between terms of sequence. For the first 22 odd numbers these are: n = 22 a = 1 d = 2 → sum = 22/2(2×1 + (22 - 1)×2)) = 22² = 484 The sum of the first n odd numbers is always n²: sum = n/2(2×1 + (n-1)2) = n/2(1 + (n-1))×2 = n(n) = n²
Find the difference between the sum of the first 1000000 positive even numbers and the sum of the first 1000000 positive odd numbers?
The sum of the first 1,000,000 positive even numbers is: 2 + 4 + 6 + 8 + ... + 2,000,000 The sum of the first 1,000,000 positive odd integers is: 1 + 3 + 5 + 7 + ... + 1,999,999 The difference between the two is: (2-1) + (4-3) + (6-5) + (8-7) + ... + (2,000,000-1,999,999). This is the same as: 1 + 1 + 1 + 1 + ... + 1. Well how many 1's are there? 1,000,000. So the difference is 1,000,000. Note that if the question asked for the difference between the sum of the first 1,000 positive even numbers and the sum of the first 1,000 positive odd numbers, the answer would be 1,000. The first n even numbers and odd numbers? n.
A rule in terms of n for the sum of the first n odd positive integers is?
n2+n
What is a rule in terms of n for the sum of the first n odd positive integers is?
Sn = n^2
Sum of squares of odd integers?
The formula for the sum of the squares of odd integers from 1 to n is n(n + 1)(n + 2) ÷ 6. EXAMPLE : Sum of odd integer squares from 1 to 15 = 15 x 16 x 17 ÷ 6 = 680
Three odd consecutive integers whose sum is 176?
First of all, the sum of 3 odd numbers always equals an odd number and 176 is even so this is NOT possible.If you did not know this you could let n be the first odd number, n+2 is the next and n+4 is the third.Add them up and we have n+n+2+n+4=176 or3n+6=176 so3n=170Now you see that 170 is NOT divisible by 3 so ONCE again you see that there is NO solution to this problem. That is to say, there are NOT 3 odd consecutive integers whose sum is 176.
How do you find the sum of the first thirty odd integers?
The arithmetic sequence of odd integers is 1, 3, 5, 7, 9, ... where the common difference is 2. The sum of the first thirty odd integers can be found by using the sum formula such as: Sn = n/2[2a1 + (n - 1)d], where a1 = 1, n = 30, and d = 2. So, S30 = (30/2)[(2)(1) + (30 - 1)(2)] = (15)[2 + (29)(2)] = (15)(60) = 900
The sum of three concecutive integers is even true or false?
False. let the integers be n, n+1 and n+2 3n+3 is there sum and we need this to be even for all integers n. if n is odd, then 3n is odd ( take n=5 3x5=15 odd) any odd number +3 is even. if n is even, then 3n is even and an even number plus and 3 is odd so the answer is false You could just say or prove it is false with a single counter example. Take the 3 consecutive integers, 2,3,4 their sum is 9 and you are done. I mentioned the 3n+3 so you can see why it is false for even set of 3 when the first of the 3 consecutive numbers is even.
How should the equation be set up to find the sum of two consecutive odd integers is 24 Find the integers?
n(n+2)(n+4) = 24
The sum of four consecutive odd integers is -72 Write an equation to model this situation and find the values of the four integers?
let n = first odd number; n + 2 = 2nd odd number ,etc. n + n+2 + n+4 + n +6 = 4n + 12 = -72 4n = -84 n = -21 -21,-19,-17 and -15
How do you prove 2n is the sum of two odd consecutive integers?
2n can be split into 2 n's so: n+n then add one to one of the n's and subtract one from one of the n's n+1+n-1 ^two consecutive odd integers^
What are the sum of the integers from 1 to 55?
Sum of first n integers is n/2 times n + 1 ie 27.5 x 56 which is 1540
Why is the sum of 2 consecutive integers always an odd number?
The sum of two even numbers is always an even number. The sum of two odd numbers is always an even number.The sum of an even number and an odd number is always an odd number.Because integers alternate between even and odd, adding two consecutive integers will always result the sum of an odd number and an even number, which, as stated above, will always be an odd number.Another way to look at it:An even number is divisible by 2, therefore, 2*n (where n is an integer) is always an even number.2*n+1 would be the next number after 2*n (so 2*n & 2*n+1 are consecutive integers).If we add these numbers together, we get 4*n+1 = 2(2*n)+1. Since 2(2*n) is an even number, adding 1 makes it an odd number._________________________________________________________________________I'm not going to but in or anything, seriously that was a good answer
The sum of three consecutive odd integers is 363 what are the numbers?
The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.
