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48 & 336; 144 & 240;

For inf, this was calculated by dividing 384 by 48, giving 8. This means that the numbers sought are multiples of 48 by two numbers totalling 8. 1/7 and 3/5 are the only answers which fit the question as 2/6 would mean the HCF was 96 (96 and 288).

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Q: Sum of two numbers is 384.what are possible numbers if there HCF is 48?
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The sum of two numbers is 384what are the possible numbers if their HCF is 48?

If the two numbers have a hcf of 48 then both numbers must be multiples of 48. 384 ÷ 48 = 8 .........Taking the paired factors of 48 of both numbers then the sum of the other factors = 8 but there can be no other common factor. 1 + 7 = 8, 3 + 5 = 8 are solutions but 2 + 6 = 8 and 4 + 4 = 8 are not, as further common factors of 2 and 4 respectively are present which would increase the hcf to 96 and 192. The numbers are 1 x 48 and 7 x 48 → 48 and 336 and.....................3 x 48 and 5 x 48 → 144 and 240


If the HCF and LCM of two numbers are 17 and 102 respectively and the HCF and LCM of two other numbers are 68 and 476 respectively then find the sum of the HCF and LCM of these four numbers?

HCF of 17 and 68 is 17 ..( Lowest Prime factor ) LCM Of 102 and 476 is 7*2^2*3*17 which is 1428 .. ==> Sum of HCF and LCM are 1428+17= 1445 .


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The HCF of the given three numbers is 9 and because the digital sum of the given numbers equals 9 then the numbers are all divisible by 9


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Is it possible for sum of 2 consecutive even numbers to equal the sum of 2 consecutive odd numbers?

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