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It is 10C4 = 10!/(6!*4!) = 10*9*8*7/(4*3*2*1) = 210

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Q: Suppose that 10 fair coins are tossed Find the numbers of ways of obtaining exactly 4 heads?
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Related questions

What is probability of obtaining a number different from 11 when a single fair die is tossed?

A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.


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The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.


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What is probability of obtaining a number different from 12 when a single fair die is tossed?

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If 3 fair coins are tossed what is the probability of getting exactly 2 tails?

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If nine fair coins are tossed what is the probability of obtaining at least one head and at least one tail using the complement formula?

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