It is 10C4 = 10!/(6!*4!) = 10*9*8*7/(4*3*2*1) = 210
1 in 12 chance
The probability is 3/4.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
3
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.
1 in 12 chance
The probability is 3/4.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
8.
3
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
3/8ths
assuming we are talking about standard dice here (six sided, numbered 1-6) then the probability of obtaining a result other than 12 when a single die is tossed is 100%. There is no way to roll a 12 after 1 toss of 1 die, therefore the chance of getting anything other than 12 is guaranteed
The probability is 3/8 = 0.375
3 out of 8
255/256 (complement formula)