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The square is 1 more than the other calculation.

The proof is quite simple: Let the numbers be x, x + 1 and x + 2

(x + 1)2 = x2 + 2x + 1;

x times x + 2 = x2 + 2x.

There is a difference of 1 whatever the value of x.

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Q: Take three consecutive numbers square the middle one and multiply the first by the third and what do you notice?
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